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首页 > 解决方案 > 如何在没有密钥的 Swift 5 可解码协议中解码字典数组类型的属性？

ios - 如何在没有密钥的 Swift 5 可解码协议中解码字典数组类型的属性？

问题描述

下面的 JSON 响应没有字典数组的键和内容。

[
  {
    "content": "You can't program the monitor without overriding the mobile SCSI monitor!",
    "media": [
      {
        "title": "Bedfordshire backing up copying",
      }
    ],
    "user": [
      {
        "name": "Ferne",
      }
    ]
  }
]

我正在尝试使用以下结构使用可解码协议解码此 JSON

struct Articles: Decodable {
  var details: ArticleDetails
  
  init(from decoder: Decoder) throws {
    let container = try decoder.singleValueContainer()
    details = try container.decode(ArticleDetails.self)
  }
}

struct ArticleDetails: Decodable {
  var content: String
  var media: [Media]
  var user: [User]
  
  enum Keys: String, CodingKey {
    case content
    case media
    case user
  }
  
  init(from decoder: Decoder) throws {
    let container = try decoder.container(keyedBy: Keys.self)
    content = try container.decode(String.self, forKey: .content)
    media = try container.decode([Media].self, forKey: .media)
    user = try container.decode([User].self, forKey: .user)
  }
}

struct Media: Decodable {
  var title: String
  
  enum Keys: String, CodingKey {
    case title
  }
  
  init(from decoder: Decoder) throws {
    let container = try decoder.container(keyedBy: Keys.self)
    title = try container.decode(String.self, forKey: .title)
  }
}

struct User: Decodable {
  var name: String
  
  enum Keys: String, CodingKey {
    case name
  }
  
  init(from decoder: Decoder) throws {
    let container = try decoder.container(keyedBy: Keys.self)
    name = try container.decode(String.self, forKey: .name)
  }
}

并使用以下解码响应

let response = try JSONDecoder().decode(Articles.self, from: data)

或者

let response = try JSONDecoder().decode([ArticleDetails].self, from: data)

但得到错误

“预期解码 Dictionary<String, Any> 但找到了一个字符串/数据。”

如何解码这样的 JSON 响应，其中没有键的字典内容数组？

标签： iosjsonswiftdictionarycodable

解决方案

模型：

struct Articles: Decodable {
    let content: String
    let media: [Media]
    let user: [User]
}

struct Media: Decodable {
    let title: String
}

struct User: Decodable {
    let name: String
}

解码：

do {
    let response = try JSONDecoder().decode([Articles].self, from: data)
    print(response)
} catch { print(error) }

（这已经在您之前的帖子中发布过。已被删除。）

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