首页 > 解决方案 > 传感器的 C 代码仅打印输出一次并退出

问题描述

我是一个 C 菜鸟,我有这个代码,它应该使用树莓派上的 IR 传感器测量体温。该代码工作正常,但它不能在循环模式下工作,只打印一次温度并退出。虽然我希望它连续运行,直到用户按下某个中断键/被用户杀死。

//gcc mlx90614.c -o mlx90614 -l bcm2835
#include <stdio.h>
#include <bcm2835.h>
#include <stdlib.h>
#include <fcntl.h>
#include <string.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <unistd.h>
#include <time.h>
#define AVG 1   //averaging samples
 
 
int main(int argc, char **argv)
{
    unsigned char buf[6];
    unsigned char i,reg;
    double temp=0,calc=0, skytemp,atemp;
    bcm2835_init();
    bcm2835_i2c_begin();
    bcm2835_i2c_set_baudrate(25000);
    // set address
    bcm2835_i2c_setSlaveAddress(0x5a);
 
    printf("\ndevice is working!!\n");
 
    calc=0;
    reg=7;
 
    for(i=0;i<AVG;i++)
    {
        bcm2835_i2c_begin();
        bcm2835_i2c_write (&reg, 1);
        bcm2835_i2c_read_register_rs(&reg,&buf[0],3);
        temp = (double) (((buf[1]) << 8) + buf[0]);
        temp = (temp * 0.02)-0.01;
        temp = temp - 273.15;
        calc+=temp;
        sleep(1);
    }
 
    skytemp=calc/AVG;
    calc=0;
    reg=6;
 
    for(i=0;i<AVG;i++){
        bcm2835_i2c_begin();
        bcm2835_i2c_write (&reg, 1);
        bcm2835_i2c_read_register_rs(&reg,&buf[0],3);
        temp = (double) (((buf[1]) << 8) + buf[0]);
        temp = (temp * 0.02)-0.01;
        temp = temp - 273.15;
        calc+=temp;
        sleep(1);
    }
 
    atemp=calc/AVG;
 
    printf("ambient temperature = %04.2f\n", atemp);
    printf("object temperature = %04.2f\n", skytemp);
 
    printf("done\n");
 
    return 0;
}

编译

gcc mlx90614.c -o mlx90614 -l bcm2835
sudo ./mlx90614

输出

device is working!!
ambient temperature = 30.06
object temperature=31.04
done

标签: craspberry-pisensors

解决方案


你需要一个无限循环。例如:

printf("\ndevice is working!!\n");
while(1)
{
    calc=0;
    reg=7;
    ...
    printf("ambient temperature = %04.2f\n", atemp);
    printf("object temperature = %04.2f\n", skytemp);
}
printf("done\n");

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