linux - 当我没有文件但只有一行的长字符串时，如何在 grep 中使用反转“-v”？

Question

假设我有

echo "The first part. The second part. The third part."

并希望删除The first part并The third part获得：

The second part.

我试过了：

echo "The first part. The second part. The third part." | grep -v -e "The first part." -e "The third part."

但是反转标志似乎仅适用于具有多行的文件。我怎样才能为单个字符串做到这一点？

标签： linuxgrep

Answer 1

改用sed：

echo "The first part. The second part. The third part." \
| sed -e 's/[[:space:]]*The first part\.[[:space:]]*//g' \
      -e 's/[[:space:]]*The third part\.[[:space:]]*//g'