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java - 缓冲阅读器抛出异常

问题描述

我想打印 hello “t” 次。所以，我写了这个代码片段。


import java.util.*;
import java.io.*;

class Buff
{
    public static void main(String args[])
    {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
        
        int t = Integer.parseInt(br.readLine());
        while(t-->0)
            bw.write("hello");

    }
}

它输出异常


Buff.java:11: error: unreported exception IOException; must be caught or declared to be thrown
                String t = br.readLine();
                                      ^
Buff.java:14: error: unreported exception IOException; must be caught or declared to be thrown
                        bw.write("hello");

请帮忙 ！！！ PS：即使我抛出 IOException 也无济于事

标签： javaloopsbufferedreaderioexceptionbufferedwriter

解决方案

您必须捕获可能的异常（在这种情况下IOException）。

基本语法如下所示：

try {
    //Your code here
}
catch(IOException e) {
    //What do you want to do when something went wrong?
}

在您的情况下，以下代码将起作用：

import java.util.*;
import java.io.*;

class Buff
{
    public static void main(String args[])
    {
        try {
            BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
            BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
            
            int t = Integer.parseInt(br.readLine());

            //Closing Readers and Writers when not needed anymore is good-practice
            br.close();

            //"-->" wasn't working for me in this case
            while(t > 0) {
                bw.write("hello\n");
                t--;
            }
            bw.flush();
            bw.close();
        }

        //Catching possible exceptions
        catch(IOException e) {
            e.printStackTrace();
        }

    }
}

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