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sql - Oracle 联接语法中具有多个条件的外部联接

问题描述

我有下面的表格

create table xx_base_tbl
(
    tbl_id      number
,   trx_num     varchar2(100)
);


create table xx_dtl_tbl
(
    dtl_id      number
,   tbl_id      number
,   category    varchar2(100)
,   attribute1  varchar2(100)
);

insert into xx_base_tbl (tbl_id, trx_num) values (1, 'trx 1');
insert into xx_base_tbl (tbl_id, trx_num) values (2, 'trx 2');
insert into xx_base_tbl (tbl_id, trx_num) values (3, 'trx 3');
insert into xx_base_tbl (tbl_id, trx_num) values (4, 'trx 4');
insert into xx_base_tbl (tbl_id, trx_num) values (5, 'trx 5');

insert into xx_dtl_tbl (dtl_id, tbl_id, category, attribute1) values (1, 1, null, 'SAMPLE');
insert into xx_dtl_tbl (dtl_id, tbl_id, category, attribute1) values (2, 1, null, 'hello');
insert into xx_dtl_tbl (dtl_id, tbl_id, category, attribute1) values (3, 2, 'PREPAYMENT', 'this is not a value');
insert into xx_dtl_tbl (dtl_id, tbl_id, category, attribute1) values (4, 2, 'PREPAYMENT', 1);
insert into xx_dtl_tbl (dtl_id, tbl_id, category, attribute1) values (5, 3, 'PREPAYMENT', 2);
insert into xx_dtl_tbl (dtl_id, tbl_id, category, attribute1) values (6, 3, 'PREPAYMENT', 1);
insert into xx_dtl_tbl (dtl_id, tbl_id, category, attribute1) values (7, 3, 'SAMPLE', 15678);
insert into xx_dtl_tbl (dtl_id, tbl_id, category, attribute1) values (8, 4, 'PREPAYMENT', 1);
insert into xx_dtl_tbl (dtl_id, tbl_id, category, attribute1) values (9, 4, 'PREPAYMENT', NULL);
insert into xx_dtl_tbl (dtl_id, tbl_id, category, attribute1) values (10, 5, 'PREPAYMENT', null);
insert into xx_dtl_tbl (dtl_id, tbl_id, category, attribute1) values (11, 5, 'SAMPLE', 'YEY');

我正在使用下面的 ANSI 语法将 xx_dtl_tbl 外部连接到另一个 xx_base_tbl 仅显示具有 PREPAYMENT 和数值的 CATEGORY。然后用于LISTAGG()将结果聚合到一行中

SELECT
    xx1.trx_num,
    LISTAGG(xx3.trx_num, ',') WITHIN GROUP(
        ORDER BY
            xx3.trx_num
    ) prepayment
FROM
         xx_base_tbl xx1
    INNER JOIN xx_dtl_tbl   xx2 ON xx1.tbl_id = xx2.tbl_id
    LEFT JOIN xx_base_tbl  xx3 ON (to_number(xx2.attribute1) = xx3.tbl_id and length(TRIM(translate(xx2.attribute1, ' +-.0123456789', ' '))) IS NULL)    
GROUP BY
    xx1.trx_num

结果看起来不错：

TRX_NUM     PREPAYMENT
-------     -------------
trx 1   
trx 2       trx 1
trx 3       trx 1,trx 2
trx 4       trx 1
trx 5

但是，当我使用SQL Developer 的工具将语法更改为 Oracle Join Syntax时，它得到以下结果：

SELECT
    xx1.trx_num,
    LISTAGG(xx3.trx_num, ',') WITHIN GROUP(
        ORDER BY
            xx3.trx_num
    ) prepayment
FROM
    xx_base_tbl  xx1,
    xx_dtl_tbl   xx2,
    xx_base_tbl  xx3
WHERE
        xx1.tbl_id = xx2.tbl_id
    AND to_number(xx2.attribute1) = xx3.tbl_id (+)
    AND ( length(TRIM(translate(xx2.attribute1, ' +-.0123456789', ' '))) IS NULL )
GROUP BY
    xx1.trx_num

结果变了：

TRX_NUM     PREPAYMENT
-------     -------------
trx 2       trx 1
trx 3       trx 1,trx 2
trx 4       trx 1
trx 5

trx 1 行突然丢失。我怎样才能用 Oracle 语法写这个？

标签： sqloraclejoinleft-joinoracle-sqldeveloper

解决方案

这个查询不太容易转换为旧语法。对我有用的是：

select a.trx_num,
       listagg(b.trx_num, ',') within group (order by b.trx_num) prepayment 
  from (

    select trx_num, attribute1, 
           case when trim(translate(xx2.attribute1, ' +-.0123456789', ' ')) is null 
                then to_number(xx2.attribute1) 
           end attr_num
    from xx_base_tbl xx1, xx_dtl_tbl xx2 
    where xx1.tbl_id = xx2.tbl_id) a, 
  
    xx_base_tbl b
  
  where a.attr_num = b.tbl_id (+)
  group by a.trx_num

小提琴手

两个步骤，首先在子查询中使用创建连接列case when，然后在主查询中使用它。

编辑：

上面的查询可以简化为：

select xx1.trx_num,  
       listagg(xx3.trx_num, ',') within group (order by xx3.trx_num) prepayment
from xx_base_tbl xx1, xx_dtl_tbl xx2, xx_base_tbl xx3
where xx1.tbl_id = xx2.tbl_id
  and case when trim(translate(xx2.attribute1, ' +-.0123456789', ' ')) is null 
            then to_number(xx2.attribute1) 
       end = xx3.tbl_id(+)
group by xx1.trx_num

小提琴手

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