javascript - 如何通过将对象作为参数传递来调用 javascript/typescript 构造函数？

Question

如果我使用以下代码调用它，我应该如何编写我的构造函数

const person = new Person({
    name,
    gender
})

其中名称和性别都是字符串

更新：

这是我在打字稿中得到的：

interface Details {
  name: string;
  gender: string;
}

class Person {
  name: string;
  gender: string;
  constructor({ name, gender }: Details) {
    this.name = name;
    this.gender = gender;
  }
}
const person = new Person({
  name: "John",
  gender: "male",
});

console.log(person);

标签： javascripttypescriptobjectconstructorparameter-passing

Answer 1

工作代码！！

在JavaScript中

class Person {
  constructor({name, gender}) {
    this.name = name;
    this.gender = gender;
  }
}
const name = 'John';
const gender = 'male';
const person = new Person({
  name,
  gender
});
console.log(person);

在打字稿中

interface Details {
  name: string;
  gender: string;
}

class Person implements Details {
  constructor({ name, gender }: Details) {
    this.name = name;
    this.gender = gender;
  }
}
const name = 'John';
const gender = 'male';
const person = new Person({
  name,
  gender
});

console.log(person);