首页 > 解决方案 > JSON序列化 - 如何不使用整个结构序列化一个类属性

问题描述

我想序列化一些字符串 json(我使用 Spring Boot):

{
  "commandId": "34d3a914-a3d7-112a-bs37-3452ac130002",
  "status": "SUCCESS",
  "response": {
    "prop1": "",
    "prop2": "",
    "prop3": "true",
    "prop4": ""
  }
}

我的映射器:

private static final ObjectMapper mapper = new ObjectMapper();

public static <T> T fromJson(String json, TypeReference<T> type) {
    T t;
    try {
      t = mapper.reader().forType(type).readValue(json);
    } catch (IOException e) {
      String message = "Error converting from json";
      log.error(message, e);
      throw new IllegalArgumentException(message);
    }

映射器的使用:

final Command command =
              JsonUtils.fromJson(json, new TypeReference<Command>() {});

命令类:

public class Command {
  private UUID commandId;
  private status status;
  private String response;
  private String error;
}

目前我收到错误:

com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of `java.lang.String` out of START_OBJECT token

我想在 Mongo dbresponse字段中保存为字符串,稍后在从 DB 接收到该对象后,我可以反序列化整个对象。是否有任何注释告诉 Json 映射器不要序列化response字段内的结构?

标签: javajsonspring-bootjson-deserializationjson-serialization

解决方案


除了使用反序列化器之外,另一种更简单的方法是在 Command 类中使用@JsonProperty注释。

public class Command {
  private UUID commandId;
  private String status;
  private String response;
  private String error;

  public UUID getCommandId() {
    return commandId;
  }

  @JsonProperty("commandId")
  public void setCommandId(String commandId) {
    this.commandId = UUID.fromString(commandId);
  }

  public String getStatus() {
    return status;
  }

  public void setStatus(String status) {
    this.status = status;
  }

  public String getResponse() {
    return response;
  }

  @JsonProperty("response")
  private void setResponse(Map<String, String> response) {
    this.response = response.toString();
  }

  public String getError() {
    return error;
  }

  public void setError(String error) {
    this.error = error;
  }
}

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