首页 > 解决方案 > SQLlite 数据库在 android studio 4 中无法正常工作

问题描述

我正在学习如何处理 SQLLite 数据库以在 android studio 中存储数据。我已经编写了如下代码,它应该在控制台上记录 2 个条目,但它没有发生。谁能告诉我为什么?

import androidx.appcompat.app.AppCompatActivity;
import android.database.Cursor;
import android.database.sqlite.SQLiteDatabase;
import android.os.Bundle;
import android.util.Log;

public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    SQLiteDatabase myDatabase = this.openOrCreateDatabase("Users", MODE_PRIVATE, null);
    myDatabase.execSQL("CREATE TABLE IF NOT EXISTS users (name VARCHAR2, age INT(3))");
    myDatabase.execSQL("INSERT INTO users(name, age) VALUES('Sajid', 22)");
    myDatabase.execSQL("INSERT INTO users(name, age) VALUES('Shoaib', 28)");

    Cursor c = myDatabase.rawQuery("SELECT * FROM users", null);
    int nameIndex = c.getColumnIndex("name");
    int ageIndex = c.getColumnIndex("age");
    c.moveToFirst();
    while(c!=null)
    {
        Log.i("Name", c.getString(nameIndex));
        Log.i("Age", c.getString(ageIndex));
        c.moveToNext();
    }
}

}`

标签: javaandroidsqliteandroid-studio

解决方案


你的代码应该是这样的:

Cursor c = myDatabase.rawQuery("SELECT * FROM users", null);
int nameIndex = c.getColumnIndex("name");
int ageIndex = c.getColumnIndex("age");
while(c.moveToNext())
{
    Log.i("Name", c.getString(nameIndex));
    Log.i("Age", c.getString(ageIndex));
}

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