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python-3.x - 在 FactoryBoy 中，如何使用空的多对多成员字段设置我的工厂？

问题描述

我将 Django 3 与 Python 3.8 一起使用。我有以下型号...

class Coop(models.Model):
    objects = CoopManager()
    name = models.CharField(max_length=250, null=False)
    types = models.ManyToManyField(CoopType, blank=False)
    addresses = models.ManyToManyField(Address)
    enabled = models.BooleanField(default=True, null=False)
    phone = models.ForeignKey(ContactMethod, on_delete=models.CASCADE, null=True, related_name='contact_phone')
    email = models.ForeignKey(ContactMethod, on_delete=models.CASCADE, null=True, related_name='contact_email')
    web_site = models.TextField()

我创建了以下工厂（使用工厂男孩）尝试在测试中创建模型......

class CoopFactory(factory.DjangoModelFactory):
    """
        Define Coop Factory
    """
    class Meta:
        model = Coop

    name = "test model"
    enabled = True
    phone = factory.SubFactory(PhoneContactMethodFactory)
    email = factory.SubFactory(EmailContactMethodFactory)
    web_site = "http://www.hello.com"

    @factory.post_generation
    def addresses(self, create, extracted, **kwargs):
        if not create:
            # Simple build, do nothing.
            return

        if extracted:
            # A list of types were passed in, use them
            for address in extracted:
                self.addresses.add(address)
        else:
            address = AddressFactory()
            self.addresses.add( address )

    @factory.post_generation
    def types(self, create, extracted, **kwargs):
        if not create:
            # Simple build, do nothing.
            return

        if extracted:
            # A list of types were passed in, use them
            for type in extracted:
                self.types.add(type)
        else:
            print("Creating type ...\n")
            type = CoopTypeFactory()
            self.types.add( type )

但我无法创建一个多对多字段（类型）为空的工厂。我尝试了以下

@pytest.mark.django_db
def test_coop_create_with_no_types(self):
    """ Test customer model """    # create customer model instance
    coop = CoopFactory.create(types=[])
    print("size: ", coop.types.all().count())
    self.assertIsNotNone(coop)
    self.assertIsNotNone( coop.id )

但是 的值types.all().count()始终等于 1。如何正确设置具有空多对多字段的工厂？

编辑：针对给出的答案，传递工厂使用的成员字段的正确方法是什么？我试过了

@pytest.mark.django_db
def test_coop_create_with_existing_type(self):
    """ Test customer model """    # create customer model instance
    coop_from_factory = CoopFactory()
    self.assertIsNotNone(coop_from_factory)

    coop_types = coop_from_factory.types
    coop = CoopFactory.create(types=[coop_types.all().first()], addresses=coop_from_factory.addresses.all())
    self.assertIsNotNone(coop)

但出现此错误，对于“for _ in range(extracted):”行...

Traceback (most recent call last):
  File "/Users/davea/Documents/workspace/chicommons/maps/web/tests/test_models.py", line 48, in test_coop_create_with_existing_type
    coop = CoopFactory.create(types=coop_types, addresses=coop_from_factory.addresses.all())
  File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/site-packages/factory/base.py", line 564, in create
    return cls._generate(enums.CREATE_STRATEGY, kwargs)
  File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/site-packages/factory/django.py", line 141, in _generate
    return super(DjangoModelFactory, cls)._generate(strategy, params)
  File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/site-packages/factory/base.py", line 501, in _generate
    return step.build()
  File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/site-packages/factory/builder.py", line 296, in build
    postgen_results[declaration_name] = declaration.declaration.call(
  File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/site-packages/factory/declarations.py", line 622, in call
    return self.function(
  File "/Users/davea/Documents/workspace/chicommons/maps/web/tests/factories.py", line 128, in types
    for _ in range(extracted):
TypeError: 'ManyRelatedManager' object cannot be interpreted as an integer

标签： python-3.xdjangounit-testingdjango-3.0factory-boy

解决方案

解决方法是更改if extracted​​为if extracted is not None.

解释

在 Python 中，空列表是错误的1但不是None。

coop = CoopFactory.create(types=[])

空列表作为参数[]传递给后生成挂钩。typesextracted

@factory.post_generation
def types(self, create, extracted, **kwargs):
    if not create:
        # Simple build, do nothing.
        return

    if extracted:
        # A list of types were passed in, use them
        for type in extracted:
            self.types.add(type)
    else:
        print("Creating type ...\n")
        type = CoopTypeFactory()
        self.types.add( type )

由于if extracted是真值测试1，虚假空列表落到创建elsea 的块中type。因此， 的值types.all().count()等于 1。

1 https://docs.python.org/3/library/stdtypes.html#truth-value-testing

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