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python - Python 电报机器人过滤器

问题描述

我一直在制作一个机器人，用于filters=Filters.privatestart_command 然后我在 a 中使用它，MessageHandler它是代码： dp.add_handler(CommandHandler('start', start_command, filters=Filters.private)) dp.add_handler(MessageHandler(Filters .private, start_keyboard_answers))

它工作得很好，但问题是我需要在第二个过滤器内制作另一个过滤器，代码应该是这样的：

dp.add_handler(CommandHandler('start', start_command, filters=Filters.private)) dp.add_handler(MessageHandler(Filters.private, start_keyboard_answers, filters=Filters.private)) dp.add_handler(MessageHandler(Filters.private, start_keyboard_answers) )

但这是不可能的，我在第二行有两个过滤器，我该如何处理？如果你想知道我在做什么，我会把完整的项目放在这里（我在第二个键盘之后寻找其他按钮，就像我对第一个和第二个所做的那样）：

from telegram.ext import Updater, Filters, CommandHandler, MessageHandler
from telegram import ReplyKeyboardMarkup

BOT_TOKEN = ''

def start_command(update, context):
    chat_id = update.message.chat.id
    context.bot.send_message(
        chat_id=chat_id,
        text='Hey, welcome to Chocolate Coffee!'
    )
    keyboard = [
        ['Make an Order']
    ]
    context.bot.send_message(
        chat_id=chat_id,
        text='How can I help you?',
        reply_markup=ReplyKeyboardMarkup(keyboard, one_time_keyboard=True, resize_keyboard=True)
    )

def start_keyboard_answers(update, context):
    message_text = str(update.message.text)
    if message_text.lower() == 'make an order':
        update.message.reply_text(
            text='Okay :)',
            quote=True
        )
        keyboard = [
            ['breakfast'],
            ['coffee'],
            ['milkshake'],
            ['colddrink'],
            ['food'],
            ['mocktail'],
            ['icecream'],
            ['organic'],
            ['smoothi'],
            ['glossy'],
            ['tea']
        ]
        chat_id = update.message.chat.id
        context.bot.sendMessage(chat_id,"ok, then?",reply_markup = ReplyKeyboardMarkup(keyboard, one_time_keyboard=True, resize_keyboard=True))
        
        message_text = str(update.message.text)
        import pdb; pdb.set_trace()
        if message_text.lower() == 'breakfast':
            update.message.reply_text(
                text='Okay :)',
                quote=True
            )
def main():
    updater = Updater(token=BOT_TOKEN, use_context=True)
    dp = updater.dispatcher

    dp.add_handler(CommandHandler('start', start_command, filters=Filters.private))
    dp.add_handler(MessageHandler(Filters.private, start_keyboard_answers))

    updater.start_polling()
    print('Started!')
    updater.idle()

if __name__ == "__main__":
    main()

标签： pythontelegram-botpython-telegram-bot

解决方案

的第一个论点MessageHandler是filters

我们可以使用按位运算符（-AND &、|-OR、~-NOT）链接多个过滤器，并将其作为第一个参数传递。像这样，

MessageHandler(filters = Filters.private & Filters.chat([ADMINS ID here]), callbacks = who_do_you_wanna_call_here)

或者干脆

MessageHandler(Filters.private & Filters.command, start_cmd_ck)

尽管从代码中，我可以看出您需要ConversationHandler安排与用户的逐步对话。在此处查看此示例

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