python-3.x - 如何在列表python中检查列表中的相同值

Question

inp = [['t', 80, 500.0], ['g', 135, 1500.0], ['t', 80, 8000.0],['g', 170, 1500.0],['g', 135, 1000.0]]

如果前两个值是相同的和第三个值并将新项目保存在一个新列表中，如下所示：inp1 = [['t', 80, 8500.0], ,['g', 170, 1500.0],['g', 135, 2500.0]]

标签： python-3.x

Answer 1

inp = [['t', 80, 500.0], ['g', 135, 1500.0], ['t', 80, 8000.0],['g', 170, 1500.0],['g', 135, 1000.0]]

dic = {x+"-"+str(y):z for (x,y,z) in inp}
inp1 = [x[0].split("-") + [sum([n[2] for n in inp if x[0]==n[0]+"-"+str(n[1])])] for x in dic.items()]

print(inp1)
# [['t', '80', 8500.0], ['g', '135', 2500.0], ['g', '170', 1500.0]]