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javascript - html body的背景颜色效果按钮的背景颜色

问题描述

我有一个小的 html 应用程序，它只会将 html 正文的背景颜色更改为随机生成的十六进制颜色。我遇到的问题是，当我单击按钮时，新的背景颜色不仅出现在正文上，而且还会影响按钮的背景颜色。在我的 css 中，我定义了按钮的背景颜色应该始终相同。

您知道如何保持按钮的背景颜色始终相同且独立于正文吗？

按钮内部的背景颜色不好

这是我的代码：

var button = document.getElementById('btn')

function createColorSegment(value) {
    const Segment = {}
    Segment.value = value
    return Segment
}

button.onclick = function() {
    const r1 = createColorSegment(undefined)
    const r2 = createColorSegment(undefined)
    const g1 = createColorSegment(undefined)
    const g2 = createColorSegment(undefined)
    const b1 = createColorSegment(undefined)
    const b2 = createColorSegment(undefined)

    function HexadecimalColor(colorSegment) {
        var numberOfColorSegment = Math.floor(Math.random() * 16)

        if (numberOfColorSegment == 10) {
            colorSegment.value = 'a'
        }
        else if (numberOfColorSegment == 11) {
            colorSegment.value = 'b'
        }
        else if (numberOfColorSegment == 12) {
            colorSegment.value = 'c'
        }
        else if (numberOfColorSegment == 13) {
            colorSegment.value = 'd'
        }
        else if (numberOfColorSegment == 14) {
            colorSegment.value = 'e'
        }
        else if (numberOfColorSegment == 15) {
            colorSegment.value = 'f'
        }
        else {
            colorSegment.value = numberOfColorSegment
        }
    }

    HexadecimalColor(r1)
    HexadecimalColor(r2)
    HexadecimalColor(g1)
    HexadecimalColor(g2)
    HexadecimalColor(b1)
    HexadecimalColor(b2)
    
    console.log(r1.value)
    console.log(r2.value)
    console.log(g1.value)
    console.log(g2.value)
    console.log(b1.value)
    console.log(b2.value)
    
    
    var HexColor = "#" + r1.value + r2.value + g1.value + g2.value + b1.value + b2.value
    console.log(HexColor) 
    
    document.getElementsByTagName('body')[0].style.backgroundColor = HexColor
    document.getElementsByClassName('hex-color-name')[0].innerText = "HEX COLOR: " + HexColor
}
* {
    padding: 0;
    margin: 0;
}

body {
    display: flex;
    justify-content: center;
}

.container {
    position: absolute;
    top: 50%;
    transform: translateY(-50%);
}

.hex-color-name {
    font-family: 'Trebuchet MS';
    font-weight: bold;
    font-size: 36px;
    padding-bottom: 10px;
    text-transform: uppercase;
}

.button {
    position: absolute;
    right: 50%;
    transform: translateX(+50%);
    height: 40px;
    width: 100px;
    border-radius: 4px;
    font-size: 18px;
    font-weight: bold;
    cursor: pointer;
    background-color:rgba(0, 0, 0, 0.6);
    color: white;
    border: 2px solid rgba(128, 128, 128, 0.8);
}

.button:hover {
    color: white;
    background-color:rgba(0, 0, 0, 0.7);
}

.button:focus {
    outline: none;
}
<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <link rel="stylesheet" href="styles.css">
    <script defer src="script.js"></script>
    <title>Project2</title>
</head>
<body>
    <div class="container">
        <div class="hex-color-name">HEX COLOR:</div>
        <button type="button" id="btn" class="button">Click me!</button>
    </div>
</body>
</html>

标签： javascripthtmlcss

解决方案

您在按钮上使用不透明度。

background-color:rgba(0, 0, 0, 0.6); <-- .6 for the alpha
border: 2px solid rgba(128, 128, 128, 0.8); <-- .8 for the alpha
background-color:rgba(0, 0, 0, 0.7); <-- .7 for the alpha

所以背景的颜色会影响按钮的颜色，因为它不是不透明的。如果您不希望这种情况发生，请不要使用不透明度。

.bg1 {
  background-color: rgba(0, 0, 0, 0.6);
}

.bg2 {
  background-color: rgb(100, 100, 100);
}
<button class="bg1">Test</button>
<button class="bg2">Test</button>

<div style="background-color: lime;">
  <button class="bg1">Test</button>
  <button class="bg2">Test</button>
</div>

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