python - 如何将笔记本的每个选项卡作为一个单独的实体？

Question

我正在尝试在 path_entry 字段中设置值。这是代码：

from tkinter import filedialog, ttk,scrolledtext
import tkinter as tk


class GUI(tk.Tk):
    def __init__(self):
        super().__init__()
        self.title("SC")
        self.geometry('375x600')
        self.resizable(width=False, height=False)
        

        names = ['Tab 1', 'Tab 2', 'Tab 3', 'Tab 4']
        self.nb = self.create_notebook(names)
        self.menu = self.create_menus()

        self.mainloop()

    def create_notebook(self, names):
        nb = MyNotebook(self, names)
        self.file_path = tk.StringVar()
        nb.pack()

       

        def path_label(parent):
            label = ttk.Label(parent, text="Person file: ").grid(column=0, row=2, padx=10, pady=10)
            return label

        def path_entry(parent):
            
            path = ttk.Entry(parent, width=30, textvariable=self.file_path).grid(column=1, row=2)
            return path

        def browse_button(parent):
            browse = ttk.Button(parent, text="Browse", command=read_csv, width=30).grid(column=1, row=3, padx=10,
                                                                                        pady=10)
            return browse

        def newapp_label(parent):
            label = ttk.Label(parent, text="Press to : ").grid(column=0, row=4, padx=10, pady=10)
            return label

        def newapp_button(parent):
            newapp = ttk.Button(parent, text="Run New Application", width=30).grid(column=1, row=4, padx=10, pady=10)
            return newapp

        def read_csv():
            file = filedialog.askopenfilename()
            if file != None:
                self.file_path.set(file)

        
        # Add some labels to each tab
        tabs = [nb.tabs['Tab 1'],nb.tabs['Tab 2'], nb.tabs['Tab 3'], nb.tabs['Tab 4']]
        for tab in tabs:
            path_label(tab)
            path_entry(tab)
            browse_button(tab)
            newapp_label(tab)
            newapp_button(tab)
        return nb

    
    def create_menus(self):
        menu = tk.Menu(self, tearoff=False)
        self.config(menu=menu)
        subMenu = tk.Menu(menu, tearoff=False)
        menu.add_cascade(label="File", menu=subMenu)
        subMenu.add_separator()
        subMenu.add_command(label='Exit', command=self.destroy)
        return menu


class MyNotebook(ttk.Notebook):
    ''' A customised Notebook that remembers its tabs in a dictionary '''

    def __init__(self, master, names):
        super().__init__(master, width=390, height=470)

        # Create tabs & save them by name in a dictionary
        self.tabs = {}
        for name in names:
            self.tabs[name] = tab = ttk.Frame(self)
            self.add(tab, text=name)


GUI()

因此，当您单击浏览按钮时，它会打开一个窗口以在该选项卡的特定条目中加载文件路径。但是我注意到所有其他选项卡的条目字段中的文件/值相同，而我希望每个选项卡都充当单独的实体。简而言之，我想为每 4 个选项卡加载四个不同文件的文件路径。怎么可能

标签： pythontkintertkinter-entry

Answer 1

这是因为您StringVar self.file_path对所有条目都使用了相同的。StringVar您应该为每个条目使用单独的：

from tkinter.scrolledtext import ScrolledText
...

def create_notebook(self, names):
    nb = MyNotebook(self, names)
    #self.file_path = tk.StringVar()
    nb.pack()

    def path_label(parent):
        label = ttk.Label(parent, text="Person file: ")
        label.grid(column=0, row=2, padx=10, pady=10)
        return label

    def path_entry(parent):
        path = ttk.Entry(parent, width=30, textvariable=parent.file_path)
        path.grid(column=1, row=2)
        return path

    def browse_button(parent):
        browse = ttk.Button(parent, text="Browse", command=lambda:read_csv(parent), width=30)
        browse.grid(column=1, row=3, padx=10, pady=10)
        return browse

    def newapp_label(parent):
        label = ttk.Label(parent, text="Press to : ")
        label.grid(column=0, row=4, padx=10, pady=10)
        return label

    def newapp_button(parent):
        newapp = ttk.Button(parent, text="Run New Application", width=30)
        newapp.grid(column=1, row=4, padx=10, pady=10)
        return newapp

    def add_scrolledtext(parent):
        text = ScrolledText(parent, width=40, height=20)
        text.grid(column=0, row=5, columnspan=2, padx=10, pady=10, sticky='nsew')
        return text

    def read_csv(parent):
        file = filedialog.askopenfilename()
        if file:
            parent.file_path.set(file)
    
    # Add some labels to each tab
    for name in names:
        tab = nb.tabs[name]
        # create a StringVar for this tab
        tab.file_path = tk.StringVar()
        path_label(tab)
        path_entry(tab)
        browse_button(tab)
        newapp_label(tab)
        newapp_button(tab)
        add_scrolledtext(tab)

    return nb

另外，您不应该写类似的东西，label = ttk.Label(...).grid(...)因为labelis 的结果grid(...)是None. 将这两个函数分成两个语句：

label = ttk.Label(...)
label.grid(...)

更新：ScrolledText在每个选项卡中添加。