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json - 解析 curl 输出

问题描述

我正在尝试解析curl请求并解析输出并将其存储在一个名为res.txt

这是我的 bash cmd 行：

    curl --request POST --url 'https://www.virustotal.com/vtapi/v2/url/scan' --data 'apikey=XXXXXXXXXXXXXXX' --data 'url=abcde.xyz' >> grep -Po '"scan_id":.*?[^\\]",' res.txt

输出是这样的：

{"permalink": "https://www.virustotal.com/gui/url/XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX/detection/u-17f485d68047604e61b4067310ab716ae6fddc774bb46ffab06d081613b28e49-1595992331", "resource": "http://abcde.xyz/", "url": "http://abcde.xyz/", "response_code": 1, "scan_date": "2020-07-29 03:12:11", "scan_id": "000000000000000000000000000000000000000", "verbose_msg": "Scan request successfully queued, come back later for the report"}`

我想在 res.txt 上存储scan_id代码，但它不起作用，没有错误！而且我不知道我的正则表达式是否正确

你能帮助我吗？

标签： jsonbashcurl

解决方案

尝试

 curl --request POST --url 'https://www.virustotal.com/vtapi/v2/url/scan' --data 'apikey=XXXXXXXXXXXXXXX' --data 'url=abcde.xyz'| tr ',' '\n' | grep scan_id

演示：


$"http://abcde.xyz/", "url": "http://abcde.xyz/", "response_code": 1, "scan_date": "2020-07-29 03:12:11", "scan_id": "000000000000000000000000000000000000000", "verbose_msg": "Scan request successfully queued, come back later for the report"}'             <
{"permalink": "https://www.virustotal.com/gui/url/XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX/detection/u-17f485d68047604e61b4067310ab716ae6fddc774bb46ffab06d081613b28e49-1595992331", "resource": "http://abcde.xyz/", "url": "http://abcde.xyz/", "response_code": 1, "scan_date": "2020-07-29 03:12:11", "scan_id": "000000000000000000000000000000000000000", "verbose_msg": "Scan request successfully queued, come back later for the report"}
$: "000000000000000000000000000000000000000", "verbose_msg": "Scan request successfully queued, come back later for the report"}' |  tr ',' '\n' | grep scan_id                                                                                                 <
 "scan_id": "000000000000000000000000000000000000000"
$

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