首页 > 解决方案 > 使用 PySpark 从数组创建整洁的数据框

问题描述

我有一个 Spark 数据框,它有两个数组,如下所示:

df = spark.createDataFrame(
  [((["Person", "Company", "Person", "Person"], 
     ["John", "Company1", "Jenny", "Jessica"]))], 
  ["Type", "Value"])
df.show()

+--------------------+--------------------+
|                Type|               Value|
+--------------------+--------------------+
|[Person, Company,...|[John, Company1, ...|
+--------------------+--------------------+

我想将其转换为如下所示的整洁版本:

df = spark.createDataFrame(
    [
        ("Person", "John"), 
        ("Company", "Company1"), 
        ("Person", "Jenny"), 
        ("Person", "Jessica"),
    ],
    ["Type", "Value"])
df.show()

+-------+--------+
|   Type|   Value|
+-------+--------+
| Person|    John|
|Company|Company1|
| Person|   Jenny|
| Person| Jessica|
+-------+--------+

PySpark 或 SparkSQL 解决方案表示赞赏。TIA。

标签: arraysapache-sparkpysparkapache-spark-sql

解决方案


Spark-2.4.0使用arrays_zip函数压缩两个数组(列表),然后执行explode.

用于创建 zip Spark < 2.4udf

Example:

df = spark.createDataFrame(
  [((["Person", "Company", "Person", "Person"], 
     ["John", "Company1", "Jenny", "Jessica"]))], 
  ["Type", "Value"])

from pyspark.sql.functions import *
df.withColumn("az",explode(arrays_zip(col("Type"),col("Value")))).select("az.*").show()
#+-------+--------+
#|   Type|   Value|
#+-------+--------+
#| Person|    John|
#|Company|Company1|
#| Person|   Jenny|
#| Person| Jessica|
#+-------+--------+

#using spark sql
df.createOrReplaceTempView("tmp")
sql("select col.* from (select explode(arrays_zip(Type,Value)) from tmp)q").show()
#+-------+--------+
#|   Type|   Value|
#+-------+--------+
#| Person|    John|
#|Company|Company1|
#| Person|   Jenny|
#| Person| Jessica|
#+-------+--------+

推荐阅读