首页 > 解决方案 > Django:如何修复 UUID ValueError('格式错误的十六进制 UUID 字符串')?

问题描述

我正在使用 Python 3.8 和 Django 3.0。

模型.py

class CustomeUser(AbstractUser):
id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False)
...

class ActivationCode(models.Model):
Code = models.CharField(max_length=30, null=False, unique=True)
ForUser = models.ForeignKey(CustomUser, null=True, blank=True, on_delete=models.CASCADE)
...

代码:

jj = {'app_id': '100',
 'color': 'blue',
 'os_type': 'MacOS',
 'time': '1596397345',
 'regKey': 'dJbeetbQ',
 'os_version': '10.15.6',
 'place_id': '20190228-3',
 'version': '2.0.0.8',
 'guid': '10614ba9b54f909a715ed518cc39741811369a11',
 'randomString': '3808651424'}

regKey = jj["regKey"]
record = ActivationCode.objects.get(Code=regKey)

当 regKey 匹配用户记录时会出现异常。如果 ForUser 字段为空,它将通过。

这里有什么问题?

完整追溯:

Traceback (most recent call last):
  File "C:\Users\Ken\anaconda3\lib\site-packages\IPython\core\interactiveshell.py", line 3331, in run_code
    exec(code_obj, self.user_global_ns, self.user_ns)
  File "<ipython-input-59-b3b355ae1522>", line 1, in <module>
    ActivationCode.objects.get(Code=regKey)
  File "C:\Users\Ken\anaconda3\lib\site-packages\django\db\models\manager.py", line 82, in manager_method
    return getattr(self.get_queryset(), name)(*args, **kwargs)
  File "C:\Users\Ken\anaconda3\lib\site-packages\django\db\models\query.py", line 411, in get
    num = len(clone)
  File "C:\Users\Ken\anaconda3\lib\site-packages\django\db\models\query.py", line 258, in __len__
    self._fetch_all()
  File "C:\Users\Ken\anaconda3\lib\site-packages\django\db\models\query.py", line 1261, in _fetch_all
    self._result_cache = list(self._iterable_class(self))
  File "C:\Users\Ken\anaconda3\lib\site-packages\django\db\models\query.py", line 74, in __iter__
    for row in compiler.results_iter(results):
  File "C:\Users\Ken\anaconda3\lib\site-packages\django\db\models\sql\compiler.py", line 1088, in apply_converters
    value = converter(value, expression, connection)
  File "C:\Users\Ken\anaconda3\lib\site-packages\django\db\backends\mysql\operations.py", line 270, in convert_uuidfield_value
    value = uuid.UUID(value)
  File "C:\Users\Ken\anaconda3\lib\uuid.py", line 160, in __init__
    raise ValueError('badly formed hexadecimal UUID string')
ValueError: badly formed hexadecimal UUID string

标签: pythonpython-3.xdjango

解决方案


此错误的根本原因仅仅是因为您在列中有一个non-UUID值。ForUser_id

正如你在评论中所说

我有一些记录它们是空的。但没有坏数据。

在我看来,好像null是什么导致了这个错误。也不建议 aUUIDField使用null值,而是使用空字符串值约定。关于使用空和空白字段选项的博客值得一读。


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