首页 > 解决方案 > 单击按钮时没有反应

问题描述

from tkinter import *
import random

def player_turn():
    if buttons['text'] == ' ':
        buttons['text'] = 'O'

def cpu_turn():
    if buttons['text'] == ' ':
        x = random.randint(1,9)
        btn_list[x]['text'] = 'X'
        
def game():
    while turns < 10 and not win:
        if turns % 2 == 1:
            player_turn()
        else:
            cpu_turn()


            
def click(buttons):
    global clicked
    global player_score
    global cpu_score
    global win
    if (btn1['text'] == 'O' and btn2['text'] == 'O' and btn3['text'] == 'O' or
        btn4['text'] == 'O' and btn5['text'] == 'O' and btn6['text'] == 'O' or
        btn7['text'] == 'O' and btn8['text'] == 'O' and btn9['text'] == 'O' or
        btn1['text'] == 'O' and btn5['text'] == 'O' and btn9['text'] == 'O' or
        btn3['text'] == 'O' and btn5['text'] == 'O' and btn7['text'] == 'O' or
        btn1['text'] == 'O' and btn4['text'] == 'O' and btn7['text'] == 'O' or
        btn2['text'] == 'O' and btn5['text'] == 'O' and btn8['text'] == 'O' or
        btn3['text'] == 'O' and btn6['text'] == 'O' and btn9['text'] == 'O'):
            player_score += 1
            win = True
    elif (btn1['text'] == 'X' and btn2['text'] == 'X' and btn3['text'] == 'X' or
        btn4['text'] == 'X' and btn5['text'] == 'X' and btn6['text'] == 'X' or
        btn7['text'] == 'X' and btn8['text'] == 'X' and btn9['text'] == 'X' or
        btn1['text'] == 'X' and btn5['text'] == 'X' and btn9['text'] == 'X' or
        btn3['text'] == 'X' and btn5['text'] == 'X' and btn7['text'] == 'X' or
        btn1['text'] == 'X' and btn4['text'] == 'X' and btn7['text'] == 'X' or
        btn2['text'] == 'X' and btn5['text'] == 'X' and btn8['text'] == 'X' or
        btn3['text'] == 'X' and btn6['text'] == 'X' and btn9['text'] == 'X'):
            cpu_score += 1
            win = True



window = Tk()
window.title('Tic Tac Toe')


buttons = StringVar()

btn1 = Button(window,text=' ',bg='red',height=4,width=8,command=lambda:click(btn1))
btn1.grid(row=1,column=0)

btn2 = Button(window,text=' ',bg='blue',height=4,width=8,command=lambda:click(btn2))
btn2.grid(row=1,column=1)

btn3 = Button(window,text=' ',bg='red',height=4,width=8,command=lambda:click(btn3))
btn3.grid(row=1,column=2)

btn4 = Button(window,text=' ',bg='blue',height=4,width=8,command=lambda:click(btn4))
btn4.grid(row=2,column=0)

btn5 = Button(window,text=' ',bg='red',height=4,width=8,command=lambda:click(btn5))
btn5.grid(row=2,column=1)

btn6 = Button(window,text=' ',bg='blue',height=4,width=8,command=lambda:click(btn6))
btn6.grid(row=2,column=2)

btn7 = Button(window,text=' ',bg='red',height=4,width=8,command=lambda:click(btn7))
btn7.grid(row=3,column=0)

btn8 = Button(window,text=' ',bg='blue',height=4,width=8,command=lambda:click(btn8))
btn8.grid(row=3,column=1)

btn9 = Button(window,text=' ',bg='red',height=4,width=8,command=lambda:click(btn9))
btn9.grid(row=3,column=2)

btn_list = [btn1,btn2,btn3,btn4,btn5,btn6,btn7,btn8,btn9]

player_score = 0
cpu_score = 0
turn = 1
win = False

当我单击按钮时,没有错误,但没有任何影响。在这里,我想在播放器和 cpu 之间的轮换中设置 while 循环,但我不知道产生这种效果的最佳方法是什么,所以有人可以教我吗?另外,如果按钮已经有文本,那么我该如何设置之后就不能点击了?想问一下lambda函数有什么用,因为不知道什么时候用

标签: pythonuser-interfacetkinter

解决方案


上面发布的代码将不会运行,因为 tkinter 框架仅在脚本包含 mainloop() 函数时可见,该函数会一直运行直到窗口关闭。

所以在最后添加以下行:

window.mainloop()

此外,由于您正在调用 click() 函数以及传递的按钮,这将是唯一要执行的函数。它不包含对以下三个函数中的任何一个的调用:

game()
cpu_turn()
player_turn()

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