python-3.x - python正则表达式从给定的目录路径中提取file_name

Question

我有一些像这样的文件夹：

../dog_breeds/images/Images/n02085620-Chihuahua
../dog_breeds/images/Images/n02085782-Japanese_spaniel
../dog_breeds/images/Images/n02086910-papillon
../dog_breeds/images/Images/n02088466-bloodhound
....
....

我只想(Chihuahua, Japanese_spaniel, papillon, bloodhound)从文件路径中提取这些信息，使用Python. 有谁能够帮我 ？

标签： python-3.xregex

Answer 1

你可以str.split在这里使用

前任：

s = """../dog_breeds/images/Images/n02085620-Chihuahua
../dog_breeds/images/Images/n02085782-Japanese_spaniel
../dog_breeds/images/Images/n02086910-papillon
../dog_breeds/images/Images/n02088466-bloodhound
"""

for p in s.splitlines():
    print(p.split("-")[-1])

---

如果你需要正则表达式。

import re

for p in s.splitlines():
    print(re.search(r"\-(\w+)$", p).group(1))

输出：

Chihuahua
Japanese_spaniel
papillon
bloodhound