c# - 从 GTK# NodeView 中获取选定的列
问题描述
我正在使用 MonoDevelop 在 Raspberry Pi 上编写一些 C# 代码。我有一个NodeView
包含三列的小部件。我想检测在 NodeView 中单击的列。我尝试使用NodeSelection.Changed
,但是,这并没有告诉我该列。我还尝试ButtonPress
为 NodeView 编写一个事件并深入到TreePath
. 我对此一无所知。
我注意到这个问题被问了好几次。但是,我还没有看到一个直接的方式来获取NodeView
.
有谁知道如何做到这一点?
解决方案
终于想通了。这很痛苦,因为正如您所说,这方面的文档为零。
当我单击不同的列时,这是输出:
Clicked on column index 3 with title "hello 3"
Node selected: Prop1 29478338;Prop2 55998661;Prop3 1058200043;Prop4 1429485106
Clicked on column index 2 with title "hello 2"
Node selected: Prop1 1781730137;Prop2 618078535;Prop3 1253079243;Prop4 1149116957
Clicked on column index 1 with title "hello 1"
Node selected: Prop1 1577113328;Prop2 1907291485;Prop3 764000225;Prop4 1871218984
Clicked on column index 0 with title "hello 0"
Node selected: Prop1 1267506574;Prop2 692394441;Prop3 1291543143;Prop4 41456018
Clicked on column index 1 with title "hello 1"
Node selected: Prop1 1659363497;Prop2 873230641;Prop3 1799765877;Prop4 83248840
Clicked on column index 2 with title "hello 2"
Node selected: Prop1 1882743696;Prop2 419098689;Prop3 554049937;Prop4 671882960
和代码一样“不漂亮”(只是快速扔东西让它工作):
Random r = new Random();
[Gtk.TreeNode(ListOnly = true)]
public class MyTreeNode : Gtk.TreeNode
{
public MyTreeNode(Random r)
{
AnotherProp1 = $"Prop1 {r.Next()}";
AnotherProp2 = $"Prop2 {r.Next()}";
AnotherProp3 = $"Prop3 {r.Next()}";
AnotherProp4 = $"Prop4 {r.Next()}";
}
[Gtk.TreeNodeValue(Column = 0)]
public string AnotherProp1 { get; private set; }
[Gtk.TreeNodeValue(Column = 1)]
public string AnotherProp2 { get; private set; }
[Gtk.TreeNodeValue(Column = 2)]
public string AnotherProp3 { get; private set; }
[Gtk.TreeNodeValue(Column = 3)]
public string AnotherProp4 { get; private set; }
public override string ToString() =>
$"{AnotherProp1};{AnotherProp2};{AnotherProp3};{AnotherProp4}";
}
private readonly NodeStore _store = new NodeStore(typeof(MyTreeNode));
public MainWindow() : base(Gtk.WindowType.Toplevel)
{
Build();
for (var i = 0; i < 6; ++i)
{
_store.AddNode(new MyTreeNode(r));
}
nodeview2.NodeStore = _store;
nodeview2.AppendColumn("hello 0", new CellRendererText(), "text", 0).Clickable = true;
nodeview2.AppendColumn("hello 1", new CellRendererText(), "text", 1).Clickable = true;
nodeview2.AppendColumn("hello 2", new CellRendererText(), "text", 2).Clickable = true;
nodeview2.AppendColumn("hello 3", new CellRendererText(), "text", 3).Clickable = true;
// how to detect column header clicks:
nodeview2.GetColumn(0).Clicked += (s, e) => Console.WriteLine("HERE 0");
nodeview2.GetColumn(1).Clicked += (s, e) => Console.WriteLine("HERE 1");
nodeview2.GetColumn(2).Clicked += (s, e) => Console.WriteLine("HERE 2");
nodeview2.GetColumn(3).Clicked += (s, e) => Console.WriteLine("HERE 3");
nodeview2.WidgetEvent += (s, e) =>
{
if ((e.Event is Gdk.EventButton ev) &&
(ev.Type == Gdk.EventType.ButtonPress) &&
(ev.Window == nodeview2.BinWindow))
{
if (nodeview2.GetPathAtPos((int)ev.X, (int)ev.Y, out var path, out var column))
{
// get the column index. There must be a better way?
var columnIndex = nodeview2.Columns.Select(
(col, index) => new { col, index }).First(x => ReferenceEquals(x.col, column)).index;
Console.WriteLine($"Clicked on column index {columnIndex} with title \"{column.Title}\"");
var nodeValue = (MyTreeNode)_store.GetNode(path);
Console.WriteLine($"Node selected: {nodeValue}");
}
}
};
nodeview2.ShowAll();
}
所以这里的诀窍是捕捉EventButton
'sButtonPress
然后获取坐标并将它们传递给GetPathAtPos()
. 这将返回列和路径信息。您可以使用它来导出您需要的内容。我希望 Gtk# 有更好的文档记录/更广泛地使用。
推荐阅读
- java - 如何在 Java 泛型方法中使用 int 代替 T?
- validation - 小数据集,训练测试拆分或训练验证和测试?
- amazon-web-services - 尝试通过 CLI 标记 Amazon FSx 时遇到问题
- shiny - 如何实现renderImage函数
- javascript - Node js和mongo更新文件中不存在的数据但数据库中存在数据
- php - 如何解决我的站点 URL 的内部服务器错误?
- google-cloud-shell - 从命令行执行 Google AI Platform Notebook
- swift - 将 UnsafePointer (#dsohandle) 转换为字符串
- python - pypi 包的 apt 依赖项
- python-3.x - 如何爬取基于 algolia-AJAX 的网站?