首页 > 解决方案 > 如何过滤两个模型之间的差异?使用 django

问题描述

我有 2 个模型,ProductProductRelatedGroupAndProductProduct有 5 个数据, [chicken, okra, ampalaya, cabbage] 和ProductRelatedGroupAndProduct有 [chicken, okra, cabbage] 我如何获得ProductRelatedGroupAndProduct没有的剩余数据?

在此处输入图像描述

选择的产品是ProductRelatedGroupAndProduct,产品列表是Product

我只想让所选产品上显示的数据不再出现在产品列表中。

到目前为止这是我的views.py

def searchrelatedproduct(request):
    id = request.GET.get('relatedproductID')
    products = Product.objects.all()
    relatedproduct = ProductRelatedGroupAndProduct.objects.filter(productrelatedgroup = id)
    return render(request, "customAdmin/relatedproduct.html",{"products":products,"relatedproduct":relatedproduct})

这是我的html

<div class="container">
    <form method="POST" action="/GroupOfProduct/" enctype="multipart/form-data">{% csrf_token %}
  <h2>Product </h2>
    <div class="form-group">
      <br>
      <label for="sel2">List Of Products</label>
            <select multiple class="form-control" id="sel2" name="product">
                {% for product in products %}
                    <option>{{product.product}}</option>
                {% endfor %}
            </select>
    </div>
      <input type="submit" style="float:right;">
  </form>
</div>


<div class="container">
  <h2>Choosen Product</h2>
  <form method="POST" action="/UpdateGroupOfProduct/" enctype="multipart/form-data">{% csrf_token %}
      <input type="submit" style="float:right;">
    <div class="form-group">
      <br>
      <label for="sel2">List Of Choosen Products</label>
        <select multiple class="form-control" id="sel2" name="relatedproduct">
          {% for product in relatedproduct %}

            <option value="{{ product.id }}">{{product.product}}</option>
          {% endfor %}
        </select>
    </div>

  </form>
</div>

这是我的models.py

class ProductRelatedGroupAndProduct(models.Model):
    product = models.ForeignKey(Product,on_delete=models.SET_NULL, null=True,blank=True,verbose_name="Product")
   productrelatedgroup = models.ForeignKey('ProductGroup',
                            on_delete=models.SET_NULL, null=True, blank=True,
                            verbose_name="ProductGroup")
class Product(models.Model):
    product = models.CharField(max_length=500)


class ProductGroup(models.Model):

    category = models.CharField(max_length=500, blank=True)

更新

当我尝试这个

diffproducts = products.exclude(pk__in=relatedproduct)
print(diffproducts)

它打印产品的所有数据

<QuerySet [<Product: cabbage>, <Product: ampalaya>, <Product: okra>, <Product: Chicken>]>

当我尝试这个时

unused_product = set(relatedproduct).difference(set(products))
print(unused_product)

***result***
{<ProductRelatedGroupAndProduct: cabbage>, <ProductRelatedGroupAndProduct: ampalaya>, <ProductRelatedGroupAndProduct: okra>}

和这个

Product.objects.filter(productrelatedgroupandproduct__isnull=True)

我得到这个错误

django.core.exceptions.FieldError: Cannot resolve keyword 'productrelatedgroupandproduct' into field

标签: pythondjango

解决方案


您可以对过滤器使用反向关系:

Product.objects.filter(productrelatedgroupandproduct__isnull=True)

productrelatedgroupandproduct这是ProductRelatedGroupAndProduct模型的小写名称。这是related_query_name参数的默认值。


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