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mysql - 如何在 JOINED 表的 SQL UNION 中 ORDER BY 未在结果中显示有序列

问题描述

我正在尝试获取两个连接结果将被联合并按几列排序的表。我发现在每个联合选择中都必须提到排序的列。但我不希望有序列出现在结果中。可能吗？也许还有其他方法可以获得我想要的结果。

这是我的查询：

SELECT coupon_id,
       coupon_name,
       real_price,
       discount_price,
       difference_percent,
       discount_percent,
       payment_price,
       photo,
       company_id,
       company_name
FROM
  (SELECT cpn.id AS coupon_id,
          cpn.name_ru AS coupon_name,
          cpn.real_price,
          cpn.discount_price,
          cpn.difference_percent,
          cpn.discount_percent,
          cpn.payment_price,
          cp.photo,
          com.id company_id,
          com.name_ru AS company_name
   FROM coupon cpn
   LEFT JOIN coupon_photo cp ON cpn.id = cp.coupon_id
   LEFT JOIN company com ON cpn.company_id = com.id
   WHERE cpn.id NOT IN
       (SELECT coupon_id AS id
        FROM transaction
        WHERE Date_add(created_time, interval 10 MINUTE) > Now()
          AND status = 'pending')
     AND cpn.exp_date > Now()
     AND cpn.valid_date > Now()
     AND cpn.available > 0
   UNION SELECT cpn.id AS coupon_id,
                cpn.name_ru AS coupon_name,
                cpn.real_price,
                cpn.discount_price,
                cpn.difference_percent,
                cpn.discount_percent,
                cpn.payment_price,
                cp.photo,
                com.id company_id,
                com.name_ru AS company_name
   FROM coupon cpn
   LEFT JOIN coupon_photo cp ON cpn.id = cp.coupon_id
   LEFT JOIN company com ON cpn.company_id = com.id
   LEFT JOIN transaction trans ON cpn.id = trans.coupon_id
   WHERE cpn.exp_date > Now()
     AND cpn.valid_date > Now()
     AND Date_add(trans.created_time, interval 10 MINUTE) > NOW()
     AND trans.status = 'pending'
     AND (cpn.available - trans.amount) > 0 GROUP  BY cpn.id) results
ORDER BY cpn.advertised DESC,
         cpn.sold DESC,
         cpn.views DESC

标签： mysqlsqlmariadb

解决方案

您的results子查询不包含您要尝试的列order by。您需要将它们添加到联合的两个部分。您不必将它们添加到您的选择中，但它们需要出现在子查询中，以便您可以在ORDER BY.

SELECT coupon_id,
       coupon_name,
       real_price,
       discount_price,
       difference_percent,
       discount_percent,
       payment_price,
       photo,
       company_id,
       company_name
FROM
  (SELECT cpn.id AS coupon_id,
          cpn.name_ru AS coupon_name,
          cpn.real_price,
          cpn.discount_price,
          cpn.difference_percent,
          cpn.discount_percent,
          cpn.payment_price,
          cp.photo,
          cpn.advertised,
          cpn.sold,
          cpn.views,
          com.id company_id,
          com.name_ru AS company_name
   FROM coupon cpn
   LEFT JOIN coupon_photo cp ON cpn.id = cp.coupon_id
   LEFT JOIN company com ON cpn.company_id = com.id
   WHERE cpn.id NOT IN
       (SELECT coupon_id AS id
        FROM transaction
        WHERE Date_add(created_time, interval 10 MINUTE) > Now()
          AND status = 'pending')
     AND cpn.exp_date > Now()
     AND cpn.valid_date > Now()
     AND cpn.available > 0
   UNION SELECT cpn.id AS coupon_id,
                cpn.name_ru AS coupon_name,
                cpn.real_price,
                cpn.discount_price,
                cpn.difference_percent,
                cpn.discount_percent,
                cpn.payment_price,
                cp.photo,
                cpn.advertised,
                cpn.sold,
                cpn.views,
                com.id company_id,
                com.name_ru AS company_name
   FROM coupon cpn
   LEFT JOIN coupon_photo cp ON cpn.id = cp.coupon_id
   LEFT JOIN company com ON cpn.company_id = com.id
   LEFT JOIN transaction trans ON cpn.id = trans.coupon_id
   WHERE cpn.exp_date > Now()
     AND cpn.valid_date > Now()
     AND Date_add(trans.created_time, interval 10 MINUTE) > NOW()
     AND trans.status = 'pending'
     AND (cpn.available - trans.amount) > 0 GROUP  BY cpn.id) results
ORDER BY advertised DESC,
         sold DESC,
         views DESC

正如 Strawberry 所指出的，GROUP BY当您不聚合任何内容时，这并不是最佳实践。在这种情况下，由于 MySQL 使用 ANY_VALUE()，它可能会导致意外结果。它返回 GROUP BY 组中某行的值。它返回哪一行是不确定的。这意味着它完全取决于 MySQL 服务器。

我假设您使用它来避免重复行。您应该找到另一种重复数据删除方法。

此外，执行 LEFT JOIN 但过滤 JOIN 右侧的元素与执行 INNER JOIN 相同。只要确保这与您要实现的目标一致。

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