javascript - XML DOM 循环遍历元素节点
问题描述
我正在做 W3 XML DOM 教程。我不明白为什么迭代会在输出中产生 1、3、5、7。我了解其他所有内容(我想!)有人可以帮忙解释一下吗?谢谢。
<!DOCTYPE html>
<html>
<body>
<p id="demo"></p>
<script>
var xhttp = new XMLHttpRequest();
xhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
myFunction(this);
}
};
xhttp.open("GET", "books.xml", true);
xhttp.send();
function myFunction(xml) {
var x, y, i, xlen, xmlDoc, txt;
xmlDoc = xml.responseXML;
x = xmlDoc.getElementsByTagName("book")[0];
xlen = x.childNodes.length;
y = x.firstChild;
txt = "";
for (i = 0; i < xlen; i++) {
if (y.nodeType == 1) {
txt += i + " " + y.nodeName + "<br>";
}
y = y.nextSibling;
}
document.getElementById("demo").innerHTML = txt;
}
</script>
</body>
</html>
输出是:
1 title
3 author
5 year
7 price
你好安迪,这是 xml DOM 文件,它来自https://www.w3schools.com/xml/dom_nodes.asp
<?xml version="1.0" encoding="UTF-8"?>
<bookstore>
<book category="cooking">
<title lang="en">Everyday Italian</title>
<author>Giada De Laurentiis</author>
<year>2005</year>
<price>30.00</price>
</book>
<book category="children">
<title lang="en">Harry Potter</title>
<author>J K. Rowling</author>
<year>2005</year>
<price>29.99</price>
</book>
<book category="web">
<title lang="en">XQuery Kick Start</title>
<author>James McGovern</author>
<author>Per Bothner</author>
<author>Kurt Cagle</author>
<author>James Linn</author>
<author>Vaidyanathan Nagarajan</author>
<year>2003</year>
<price>49.99</price>
</book>
<book category="web" cover="paperback">
<title lang="en">Learning XML</title>
<author>Erik T. Ray</author>
<year>2003</year>
<price>39.95</price>
</book>
</bookstore>
针对 Carlos22 的回答的补充评论。对不起,卡洛斯,我还是不明白。
(y.nodeType ==1)
将始终返回 true,因为第一次出现的子<book>
元素都是 type element (nodeType = 1)
第一个循环 i = 0
,所以 txt 的值应该是 0 title
第二个循环 i = 1
,所以0 title
应该与1 author
字符串 txt 的值连接,现在是0 title 1 author
第三个循环 i = 2
txt 包含字符串0 title 1 author 2 year
等等。
我有时会变得非常愚蠢,所以请原谅!
解决方案
您的代码仅评估“元素节点”,因为if (y.nodeType == 1)
.
这是所有节点的示例:
const xml = `<?xml version="1.0" encoding="UTF-8"?>
<bookstore>
<book category="cooking">
<title lang="en">Everyday Italian</title>
<author>Giada De Laurentiis</author>
<year>2005</year>
<price>30.00</price>
</book>
<book category="children">
<title lang="en">Harry Potter</title>
<author>J K. Rowling</author>
<year>2005</year>
<price>29.99</price>
</book>
<book category="web">
<title lang="en">XQuery Kick Start</title>
<author>James McGovern</author>
<author>Per Bothner</author>
<author>Kurt Cagle</author>
<author>James Linn</author>
<author>Vaidyanathan Nagarajan</author>
<year>2003</year>
<price>49.99</price>
</book>
<book category="web" cover="paperback">
<title lang="en">Learning XML</title>
<author>Erik T. Ray</author>
<year>2003</year>
<price>39.95</price>
</book>
</bookstore>`;
function getXmlFromText(xml) {
parser = new DOMParser();
return parser.parseFromString(xml, "text/xml");
}
function getNodeTypeStr(nodeType) {
if (nodeType == 1) return 'ELEMENT_NODE';
if (nodeType == 3) return 'TEXT_NODE';
return 'Read the DOCS: https://www.w3schools.com/xml/dom_nodetype.asp';
}
function myFunction(xmlDoc) {
var x, y, i, xlen, txt;
//xmlDoc = xml.responseXML;
x = xmlDoc.getElementsByTagName("book")[0];
xlen = x.childNodes.length;
y = x.firstChild;
txt = ""; var txt2 = '';
for (i = 0; i < xlen; i++) {
if (y.nodeType == 1) {
txt += i + " " + y.nodeName + "<br>";
}
txt2 += i + ' - ' + y.nodeName + ' - ' + getNodeTypeStr(y.nodeType) + ' - ' + y.nodeValue + '<br>';
y = y.nextSibling;
}
document.getElementById("demo").innerHTML = txt;
document.getElementById("allnodes").innerHTML = txt2;
}
myFunction(getXmlFromText(xml));
div {
padding: 2px;
border: 1px solid gray;
margin-bottom: 4px;
}
Only element nodes:
<div id="demo"></div>
All nodes:
<div id="allnodes"></div>
打包的 XML 示例:
const xml = `<?xml version="1.0" encoding="UTF-8"?>
<bookstore>
<book category="cooking">
<title lang="en">Everyday Italian</title><author>Giada De Laurentiis</author>
<year>2005</year>
<price>30.00</price>
</book>
<book category="children">
<title lang="en">Harry Potter</title>
<author>J K. Rowling</author>
<year>2005</year>
<price>29.99</price>
</book>
<book category="web">
<title lang="en">XQuery Kick Start</title>
<author>James McGovern</author>
<author>Per Bothner</author>
<author>Kurt Cagle</author>
<author>James Linn</author>
<author>Vaidyanathan Nagarajan</author>
<year>2003</year>
<price>49.99</price>
</book>
<book category="web" cover="paperback">
<title lang="en">Learning XML</title>
<author>Erik T. Ray</author>
<year>2003</year>
<price>39.95</price>
</book>
</bookstore>`;
function getXmlFromText(xml) {
parser = new DOMParser();
return parser.parseFromString(xml, "text/xml");
}
function getNodeTypeStr(nodeType) {
if (nodeType == 1) return 'ELEMENT_NODE';
if (nodeType == 3) return 'TEXT_NODE';
return 'Read the DOCS: https://www.w3schools.com/xml/dom_nodetype.asp';
}
function myFunction(xmlDoc) {
var x, y, i, xlen, txt;
//xmlDoc = xml.responseXML;
x = xmlDoc.getElementsByTagName("book")[0];
xlen = x.childNodes.length;
y = x.firstChild;
txt = ""; var txt2 = '';
for (i = 0; i < xlen; i++) {
if (y.nodeType == 1) {
txt += i + " " + y.nodeName + "<br>";
}
txt2 += i + ' - ' + y.nodeName + ' - ' + getNodeTypeStr(y.nodeType) + ' - ' + y.nodeValue + '<br>';
y = y.nextSibling;
}
document.getElementById("demo").innerHTML = txt;
document.getElementById("allnodes").innerHTML = txt2;
}
myFunction(getXmlFromText(xml));
div {
padding: 2px;
border: 1px solid gray;
margin-bottom: 4px;
}
Only element nodes:
<div id="demo"></div>
All nodes:
<div id="allnodes"></div>
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