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python - python Xpath：如何删除空标签但保留同级尾随文本？

问题描述

<div>
   1
   <br/>
   5
   <p> </p>
   2
</div>

假设我必须删除空标签。在此示例中，空标签是<p> </p>. 我创建了这个函数来为我完成这项工作。但它也会2在<p>标记后删除。那我该怎么办？


def reformat_article(text):
    tree = etree.fromstring(text, parser=etree.HTMLParser(encoding='utf-8'))
    # etree.strip_attributes(tree, 'style')
    etree.strip_tags(tree, 'span', 'font')

    for script in tree.xpath('//script'):
        script.getparent().remove(script)

    for empty in tree.xpath('//*[text() and not(*)]'):
        if re.match(r'^\s+$', ''.join(empty.xpath('./text()'))):
            empty.getparent().remove(empty)

    for empty in tree.xpath('//*[not(self::br) and not(*) and not(normalize-space()) and not(self::text())]'):
        empty.getparent().remove(empty)

    for align in tree.xpath('//*[text()]'):
        s_s = re.compile(r'\s{20,}')
        for line in align.xpath('./text()'):
            if s_s.search(line):
                align.attrib['align'] = 'right'

    text = etree.tostring(tree, encoding='utf-8').decode()
    return text

标签： pythonxpathlxml

解决方案

要删除不带尾字符串的元素，请使用以下函数：

def remove_element(el):
    parent = el.getparent()
    tail = el.tail
    if tail is not None and len(tail.strip()) > 0:
        prev = el.getprevious()
        if prev is not None:
            prev.tail = (prev.tail or '') + el.tail
        else:
            parent.text = (parent.text or '') + el.tail
    parent.remove(el)

我通过以下方式对其进行了测试：

from lxml import etree as et

parser = et.XMLParser(remove_blank_text=True)
txt = '<div>1<br/>5<p> </p>2</div>'
tree = et.XML(txt, parser)
for emp in tree.xpath('//*[text() and not(*)]'):
    remove_element(emp)
print(et.tostring(tree, method='xml', encoding='unicode',
    pretty_print=True).strip())

我得到的结果是：

<div>1<br/>52</div>

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