javascript - 有没有办法从包含特定值的对象中找到（）随机元素

Question

我有一个包含健身房及其可用设备的对象：

        const gyms = [
  {
    "name": "gym1",
    "equipmentAvailable": ["nothing"]
  },
  {
    "name": "gym2",
    "equipmentAvailable": ["jump rope","stationary bike","barbell"]
  },
  {
    "name": "gym3",
    "equipmentAvailable": ["kettlebell","dumbbell"]
  },
  {
    "name": "gym4",
    "equipmentAvailable": ["barbell","kettlebell","jump rope"]
  }
]

我还列出了下一次锻炼所需的设备清单（然后转换为套装）：

const availableNeeded = ["barbell","jump rope"]

const equipmentSet = new Set(availableNeeded);

目前我正在使用 .find() 拉出第一个符合我的设备需求的健身房：

const filteredWorkouts = gyms.find(workout => (
  workout.equipmentAvailable.some(equipment => equipmentSet.has(equipment))
))

console.log(filteredWorkouts)

自然，这总是返回gym2，因为它是第一个匹配所需设备的健身房。但是，有时我想将其切换到gym4，因为它也有所需的设备，但 find() 不会提供。

我如何随机化健身房输出，以便它可以吐出gym2或gym4？

标签： javascript

Answer 1

使用.filter而不是.find获取可能匹配的数组，然后从数组中获取随机元素：

const gyms = [
  {
    "name": "gym1",
    "equipmentAvailable": ["nothing"]
  },
  {
    "name": "gym2",
    "equipmentAvailable": ["jump rope","stationary bike","barbell"]
  },
  {
    "name": "gym3",
    "equipmentAvailable": ["kettlebell","dumbbell"]
  },
  {
    "name": "gym4",
    "equipmentAvailable": ["barbell","kettlebell","jump rope"]
  }
];
const availableNeeded = ["barbell","jump rope"];
const filteredWorkouts = gyms.filter(gym => (
  availableNeeded.every(equip => gym.equipmentAvailable.includes(equip))
));
const result = filteredWorkouts[Math.floor(Math.random() * filteredWorkouts.length)];
console.log(result);