c++ - C++ 错误：'operator<<' 不匹配（操作数类型是 'std::istream {aka std::basic_istream}' 和 'int'）

Question

所以我正在用 C++ 编写这个简单的计算器。
错误消息说：

main.cpp:38:6：错误：'operator<<' 不匹配（操作数类型为'std::istream {aka std::basic_istream}' 和'int'）
cin<<anotherQ;

代码是：

using namespace std;
int main()
{
    int running = 0;
    while(running != 1) {
        float num1;
        float num2;
        char op;
        int anotherQ;
        cout<<"Enter 1 for '+', 2 for '-', 3 for '*', 4 for '/': ";
        cin>>op;
        cout<<"\n";
        cout<<"Enter a number: ";
        cin>>num1;
        cout<<"\n";
        cout<<"Enter another number: ";
        cin>>num2;
        cout<<"\n";
        if (op=='1') {
            cout<<"The answer is "<<num1 + num2<<endl;
        }
        else if(op == '2') {
            cout<<"The answer is "<<num1 - num2<<endl;
        }

        else if(op=='3') {
            cout<<"The answer is "<<num1 * num2<<endl;
        }
        else if(op=='4') {
            cout<<"The answer is "<<num1 / num2<<endl;
        }
        else {
            cout<<"Wrong operator"<<endl;
            running = 1;
        }
        cout<<"Do you want to do another sum 0 for Yes and 1 for No "<<endl;
        cin<<anotherQ;
        if (anotherQ == 0) {
            cout<<"Hmm.., Think u like maths well let's do another sum"<<endl;
        }
        else if (anotherQ == 1) {
            cout<<"Ok well byee!"<<endl;
            running = 1;
        }
        else {
            cout<<"crrrcrr u have given a wrong command byeeeeeeeeeeeeeeeee! I was not desinged for handling such complex commands  as I was made by a 9 year old boy u will pay for it"<<endl;
            running = 1;            
        }
    }

    return 0;
}

标签： c++

Answer 1

你有

cin<<anotherQ;

在您的代码中，这是不正确的。

cin >> anotherQ;

是正确的语法。