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python - 导入功能失败，但导入功能测试有效

问题描述

我使用 myfuncs 导入我的函数，但它失败了我确实测试了相同的文件路径，只是文件名略有不同，但它失败了。python 代码已有 5 年历史，不确定是否发生了变化。

我确实去了这个线程，我做了测试，它确实成功地完成了测试，我的实际外观是一样的。

Python中的函数未定义错误

#!/usr/bin/python

# Our function is pulled in here
from myfunction import pyth_test

pyth_test(1,2)

这个测试有效，但是我的实际函数文件不是两个文件都在同一个目录中，两个导入都来自 import * 相同的格式，只是文件名略有不同，这无关紧要。

测试以查看导入是否有效

from myfunction import *

pyth_test(1,2)

这工作成功

3


however when I try the actual impor of the function I need to use I get this error
---------------------------------------------------------------------------
NameError                                 Traceback (most recent call last)
<ipython-input-5-1a2412372452> in <module>
      6 f.close()
      7 
----> 8 bag_of_words = myfuncs.get_bag_of_words(titles_lines)
      9 keywords = myfuncs.get_keywords(titles_lines, bag_of_words)

NameError: name 'myfuncs' is not defined

下面的代码是我运行以从名为 myfuncs.py 的文件中调用函数的代码

运行.py

from myfuncs import *

f = open('s2-titles.txt', encoding="utf8")
titles_lines = f.readlines()
f.close()

bag_of_words = myfuncs.get_bag_of_words(titles_lines)
keywords = myfuncs.get_keywords(titles_lines, bag_of_words)

myfuncs.py

#!/usr/bin/env python
# coding: utf-8

def get_bag_of_words(titles_lines):

    # bag of words
    bag_of_words = {}
    # [1: ]skips the first line which is the header
    for line in titles_lines[1:]:
        courseid, course_bag_of_words = get_course_bag_of_words(line)
        for word in course_bag_of_words:
                if word not in course_bag_of_words:
                    bag_of_words[word] = course_bag_of_words[word]
                else:
                    bag_of_words[word] += course_bag_of_words[word]
    return bag_of_words

def get_course_bag_of_words(line):
        course_bag_of_words = {}
        #split by weirdcombo to prevent weird splits
        courseid, title, description =  line.split('XXXYYYZZZ')
        title = title.lower()
        description = description.lower()
        wordlist = title.split() + description.split()
        if len(wordlist) >=10:
             for word in wordlist:
                if word not in course_bag_of_words:
                    course_bag_of_words[word] = 1
                else:
                    course_bag_of_words[word] += 1

        return courseid, course_bag_of_words

def get_sorted_results(d):
    kv_list = d.items()
    vk_list = []
    for kv in kv_list:
        k,v = kv
        vk = v,k
        vk_list.append(vk)
    vk_list.sort()
    vk_list.reverse()
    k_list = []
    for vk in vk_list[:10]:
        v,k = vk
        k_list.append(k)
    return k_list

def get_keywords(titles_lines, bag_of_words):
    n = sum(bag_of_words.values())
    keywords = {}
    for line in titles_lines[1:]:
        courseid, course_bag_of_words = get_course_bag_of_words(line)
        term_importance = {}
        for word in course_bag_of_words:
            tf_course =(float(course_bag_of_words[word])/
                         sum(course_bag_of_words.values())
                         )
            tf_overall = float(bag_of_words[word]) /n
            term_importance[word] = tf_course/tf_overall
        keywords[courseid] = get_sorted_results(term_importance)
        if courseid == '74953':
            for word in keywords[courseid]:
                print('has importance', term_importance['word'])
    return keywords

在此处输入图像描述

标签： pythonpython-3.xpython-import

解决方案

我能够弄清楚。看起来我不再需要 myfuncts.myfuction()加载它了just .myfuction()

我改变了这个

from myfuncs import *

f = open('s2-titles.txt', encoding="utf8")
titles_lines = f.readlines()
f.close()

bag_of_words = myfuncs.get_bag_of_words(titles_lines)
keywords = myfuncs.get_keywords(titles_lines, bag_of_words)

对此，它的工作原理会引发另一个错误，但那是另一回事了。让我现在搜索一下。

from myfuncs import *

f = open('s2-titles.txt', encoding = "utf8")
titles_lines = f.readlines()
f.close()

bag_of_words = get_bag_of_words(titles_lines)
keywords = get_keywords(titles_lines, bag_of_words)


---------------------------------------------------------------------------
KeyError                                  Traceback (most recent call last)
<ipython-input-18-916e24603531> in <module>
      5 f.close()
      6 
----> 7 bag_of_words = get_bag_of_words(titles_lines)
      8 keywords = get_keywords(titles_lines, bag_of_words)

~\django\nlp-notebooks\myfuncs.py in get_bag_of_words(titles_lines)
     13                     bag_of_words[word] = course_bag_of_words[word]
     14                 else:
---> 15                     bag_of_words[word] += course_bag_of_words[word]
     16     return bag_of_words
     17 

KeyError: 'learning'

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