java - 无法提交 JPA 事务：嵌套异常是 javax.persistence.RollbackException：提交事务时出错

Question

我查看了多个类似的实例（如下所述），其中错误几乎相同，但我发现我的情况有点不同。有人可以帮我吗？

• javax.persistence.RollbackException：事务标记为 rollbackOnly
• 无法提交 JPA 事务：事务标记为 rollbackOnly
• 还有很多。

在我的情况下，确切的异常消息是 -

Could not commit JPA transaction; nested exception is javax.persistence.RollbackException: Error while committing the transaction

当我尝试MarriagePerson保存@ManyToOne与 User. 请在下面找到实体及其关系 -

用户.java

@Entity
@Table(name = "MAIN_USER")
public class User {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;

    @OneToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL, mappedBy = "user")
    private Collection<MarriagePerson> marriagePerson = new ArrayList<MarriagePerson>();

    @NotEmpty(message = "Name can not be empty")
    @Size(min = 2, max = 20, message = "Name must be between 2 and 20 characters long")
    @Column(name = "first_name")
    private String firstName;

    @Column(name = "middle_name")
    private String middleName;

    @Column(name = "last_name")
    private String lastName;

    @NotEmpty(message = "Email can not be empty")
    @Size(min = 5, message = "Email must be more than 5 characters long")
    @Column(name = "email", unique = true)
    private String email;

    @Column(name = "alternateEmail")
    private String alternateEmail;

    @NotEmpty(message = "Mobile can not be empty")
    @Size(min = 10, max = 10, message = "Mobile must be 10 digits long")
    @Column(name = "mobile", unique = true)
    private String mobile;

    @Column(name = "alternate_mobile")
    private String alternateMobile;

    @NotEmpty(message = "Password can not be empty")
    @Size(min = 6, message = "Password must be more than 6 characters long")
    @Column(name = "password")
    private String password;
}

婚姻人.java

@Entity
@Table(name = "MARRIAGE_PERSON")
public class MarriagePerson {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;

    @ManyToOne
    @JoinColumn(columnDefinition = "user_id")
    private User user;

    @NotEmpty
    @Column(name = "gender")
    private String gender;

    @NotEmpty(message = "Name can not be empty")
    @Size(min = 2, max = 20, message = "Name must be between 2 and 20 characters long")
    @Column(name = "firstName")
    private String firstName;
}

这就是我正在做的事情 -

• 我User在我的postgres数据库中保存了一个。
• 现在我正在尝试保存MarriagePerson相同User的内容，然后捕获到上述异常。

请在下面找到UserSerive-MarriagePersonService

用户服务.java

@Service
public class UserService implements IUserService {

    @Autowired
    private IUserRepository userRepository;
    
    @Override
    public User save(User user) {
        return userRepository.save(user);
    }
}

婚姻人.java

@Service
public class MarriagePersonService implements IMarriagePersonService {

    @Autowired
    private IMarriagePersonRepository marriagePersonRepository;

    @Override
    public MarriagePerson save(MarriagePerson marriagePerson) {
        userRepository.findById(userId).map(user -> {
            marriagePerson.setUser(user);
            return marriagePersonRepository.save(marriagePerson);
        });
        return marriagePerson;
    }
}

marriagePersonRepository.save(marriagePerson);对于以下提到的请求有效负载，在此行捕获了异常-

婚姻人有效载荷

{
  "firstName": "Name",
  "gender": "Male"
}

已保存的用户数据如下（我们正在尝试更新MarriagePerson）

{
    "firstName": "string",
    "middleName": "string",
    "lastName": "string",
    "email": "[e-mail]",
    "alternateEmail": "[e-mail]",
    "mobile": "0123456789",
    "alternateMobile": "0123456789",
    "password": "string",
    "marriagePerson": []
}

编辑

存储库接口是 -

IMarriagePersonRepository.java

@Repository
public interface IMarriagePersonRepository
        extends JpaRepository<MarriagePerson, Long>, JpaSpecificationExecutor<MarriagePerson> {
    List<MarriagePerson> findAll();
}

IUserRepository.java

@Repository
public interface IUserRepository extends JpaRepository<User, Long> {
    public User findByMobile(String mobile);
    User findByMobileAndEmail(String mobile, String email);
}

先感谢您。

标签： javaspring-boothibernatespring-data-jpaspring-data