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python - 如何使用 scrapy 和 splash 从这个网站上抓取？

问题描述

我是新手，我正在尝试抓取本网站href中列出的每个地方的链接。然后我想进入每个链接并抓取数据，但我什至无法从此代码中获取 href 链接。但是，我可以在 Scrapy shell 中使用相同的 xpath 选择器来获取.href

import scrapy
from scrapy_splash import SplashRequest

class TestspiSpider(scrapy.Spider):
    name = 'testspi'
    allowed_domains = ["powersearch.jll.com"]
    start_urls = ["https://powersearch.jll.com/us-en/property/search"]
    
    def start_requests(self):
    

        for url in self.start_urls:
            yield SplashRequest(url=url,callback= self.parse, args={'wait':5})
            
    def parse(self,response):
        
        properties=response.xpath('//*[@class="ssr__container"]').extract()
        print (properties)
        print ("HELLO WORLD")

当我运行代码时，我得到一个空列表。这是输出：

2020-09-03 19:58:49 [scrapy.extensions.logstats] INFO: Crawled 0 pages (at 0 pages/min), scraped 0 items (at 0 items/min)
2020-09-03 19:58:49 [scrapy.extensions.telnet] INFO: Telnet console listening on 127.0.0.1:6023
2020-09-03 19:58:49 [py.warnings] WARNING: /Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/site-packages/scrapy_splash/request.py:41: ScrapyDeprecationWarning: Call to deprecated function to_native_str. Use to_unicode instead.
  url = to_native_str(url)

2020-09-03 19:58:59 [scrapy.core.engine] DEBUG: Crawled (200) <GET https://powersearch.jll.com/us-en/property/search via http://localhost:8050/render.html> (referer: None)
[]
HELLO WORLD
2020-09-03 19:58:59 [scrapy.core.engine] INFO: Closing spider (finished)
2020-09-03 19:58:59 [scrapy.statscollectors] INFO: Dumping Scrapy stats:
{'downloader/request_bytes': 535,
 'downloader/request_count': 1,
 'downloader/request_method_count/POST': 1,
 'downloader/response_bytes': 148739,
 'downloader/response_count': 1,
 'downloader/response_status_count/200': 1,
 'elapsed_time_seconds': 9.802616,
 'finish_reason': 'finished',
 'finish_time': datetime.datetime(2020, 9, 3, 14, 28, 59, 274213),
 'log_count/DEBUG': 1,
 'log_count/INFO': 10,
 'log_count/WARNING': 1,
 'memusage/max': 51179520,
 'memusage/startup': 51179520,
 'response_received_count': 1,
 'scheduler/dequeued': 2,
 'scheduler/dequeued/memory': 2,
 'scheduler/enqueued': 2,
 'scheduler/enqueued/memory': 2,
 'splash/render.html/request_count': 1,
 'splash/render.html/response_count/200': 1,
 'start_time': datetime.datetime(2020, 9, 3, 14, 28, 49, 471597)}
2020-09-03 19:58:59 [scrapy.core.engine] INFO: Spider closed (finished)

请帮我解决这个问题

标签： pythonweb-scrapingscrapyscrapy-splashsplash-js-render

解决方案

在您的情况下，我不认为 Splash 是必需的。

如果您通过浏览器的开发人员工具查看网页，您会看到有一个 API正在加载属性。 在此处输入图像描述

你可以有一个标准的scrapy spider调用该API并请求每个属性页面：

import json
import scrapy


class TestspiSpider(scrapy.Spider):
    name = 'testspi'

    api_url = "https://powersearchapi.jll.com/api/search/properties/v2?queries%5B0%5D.type=1&queries%5B0%5D.term=United%20States%20of%20America&queries%5B0%5D.isStateOrCountry=true&options.siteOrganizationId=11111111-1111-1111-1111-111111111111&options.unitOfMeasurement=1&options.currencyCode=USD&options.page={page}&options.perPage=24&options.sort=3&options.sortDir=1&options.searchMultiplier=1"

    start_urls = [
        api_url.format(page=1)
    ]

    def parse(self, response):
        data = json.loads(response.text)
        properties = data.get('results')

        if properties:
            # If no current page in meta, set as first page
            current_page = response.meta.get('page') or 1
            next_page = current_page + 1
            yield scrapy.Request(
                self.api_url.format(page=next_page),
                meta={
                    'page': next_page
                },
                callback=self.parse
            )

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