首页 > 解决方案 > 我想审核 alfresco 搜索表单中使用的搜索参数

问题描述

我想审核露天搜索表单中使用的搜索参数。

我正在使用版本:Alfresco Enterprise v5.1.1

如果我搜索 jbong 然后在露天日志中我想看到这样的东西: /alfresco-api/post/SearchService/query/args/searchParameters=jbong*

但它显示 /alfresco-api/pre/SearchService/query/args=null

任何帮助或建议都将受到高度评价。非常感谢。

这是我的步骤和配置的详细信息

  1. 假设我正在搜索“jbong” 在此处输入图像描述

2.但是露天日志显示如下: alfresco.log

    2020-09-08 16:58:20,480  DEBUG [repo.jscript.ScriptLogger] [http-apr-8080-exec-16] Query  :
    jbong
    Sortby:
     2020-09-08 16:58:20,483  DEBUG [repo.audit.inbound] [http-apr-8080-exec-16]
    Inbound audit values:
            /alfresco-api/pre/SearchService/query/args=null
     2020-09-08 16:58:20,757  DEBUG [repo.audit.inbound] [http-apr-8080-exec-16]
    Inbound audit values:
            /alfresco-api/post/SearchService/query/args=null
            /alfresco-api/post/SearchService/query/no-error=null
     2020-09-08 16:58:20,761  DEBUG [repo.audit.AuditComponentImpl] [http-apr-8080-exec-16]
    Extracted audit data:
            Application:    AuditApplication[ name=SearchAudit, id=12, disabledPathsId=8473501]
            Values:
                    /searchaudit/query/args=null
                    /searchaudit/query/no-error=null
    
    New Data:
    2020-09-08 16:58:20,761  DEBUG [repo.audit.AuditComponentImpl] [http-apr-8080-exec-16]
    
    Nothing audited:
            Application ID: 12
            Entry ID:       null
            Values:
                    /searchaudit/query/args=null
                    /searchaudit/query/no-error=null
    
     2020-09-08 16:58:20,765  DEBUG [repo.jscript.ScriptLogger] [http-apr-8080-exec-16] Processing resultset of length: 0
     2020-09-08 16:58:20,765  DEBUG [repo.jscript.ScriptLogger] [http-apr-8080-exec-16] Filtered resultset to length: 0. Discarded item count: 0
    

3. 这是我的自定义审计配置:

A. alfresco-home/tomcat/shared/classes/alfresco/extension/audit/SearchAudit.xml

 <?xml version='1.0' encoding='UTF-8'?>


<Audit
    xmlns="http://www.alfresco.org/repo/audit/model/3.2"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.alfresco.org/repo/audit/model/3.2 alfresco-audit-3.2.xsd"
    >

  <DataExtractors>
        <DataExtractor name="simpleValue" registeredName="auditModel.extractor.simpleValue" />
        <DataExtractor name="nullValue" registeredName="auditModel.extractor.nullValue" />
    </DataExtractors>


    <PathMappings>
        <PathMap source="/alfresco-api/post/SearchService/query" target="/searchaudit/query" />
    </PathMappings>
 
    <Application name="SearchAudit" key="searchaudit">
        <AuditPath key="query">
            <RecordValue key="store" dataExtractor="simpleValue"
                        dataSource="/searchaudit/query/args/store" dataTrigger="/searchaudit/query/no-error" />
            <RecordValue key="language" dataExtractor="simpleValue"
                        dataSource="/searchaudit/query/args/language" dataTrigger="/searchaudit/query/no-error" />
            <RecordValue key="query" dataExtractor="simpleValue"
                        dataSource="/searchaudit/query/args/query" dataTrigger="/searchaudit/query/no-error" />
        </AuditPath>
    </Application>
</Audit>

B. alfresco-global.properties

 # Audit configuration
audit.enabled=true
audit.tagging.enabled=true
audit.alfresco-access.enabled=true
audit.alfresco-access.sub-actions.enabled=true
audit.cmischangelog.enabled=true

标签: javaalfrescoalfresco-webscriptsalfresco-enterprise

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