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assembly - 无法在保护模式下打印

问题描述

我在操作系统开发链接1链接2中关注这些 教程

我无法在保护模式下打印。

这是我的代码：

$ gcc -E boot.S 
# 1 "boot.S"
# 1 "<built-in>"
# 1 "<command-line>"
# 31 "<command-line>"
# 1 "/usr/include/stdc-predef.h" 1 3 4
# 32 "<command-line>" 2
# 1 "boot.S"
# 1 "header.h" 1



read_fail:
 .asciz "Disk read failed"

.altmacro

.macro PUSHA
 push %ax
 push %bx
 push %cx
 push %dx

.endm

.macro POPA
 pop %ax
 pop %bx
 pop %cx
 pop %dx
.endm

.macro PUSH_EA
 push %eax
 push %ebx
 push %ecx
 push %edx
.endm

.macro POP_EA
 pop %eax
 pop %ebx
 pop %ecx
 pop %edx
.endm

.macro CLEAR

 PUSH_EA
 mov $0x0600, %ax
 mov $0x07, %bh
 mov $0x00, %cx
 mov $0x184f, %dx
 int $0x10
 CURSOR_POS

 POP_EA
.endm

.macro CURSOR_POS x=2, y=2
 PUSH_EA
 mov $0x02, %ah
 mov $0x00, %bh
 mov \x, %dh
 mov \y, %dl
 int $0x10
 POP_EA


.endm

.macro BEGIN
 .code16
_start:
 xor %ax,%ax
 mov %ax, %ds
 mov %ax, %es
 mov %ax, %fs
 mov %ax, %gs
 mov %ax, %ss

 mov %ax, %bp
 mov %bp, %sp

.endm

.macro PRINT_STRING str

 LOCAL loop,end
 mov \str, %si
 mov $0x0E, %ah

 cld

loop:
 lodsb

 cmp $0x00, %al
 je end

 int $0x10
 jmp loop

end:
.endm

.macro HEX_NIBBLE reg
 LOCAL end, letter
 cmp $10, \reg
 jae letter
 add $'0', \reg
 jmp end

letter:
 add $0x37, \reg
.endm

.macro HEX c
 mov \c, %al
 mov \c, %ah
 shr $4, %al
 HEX_NIBBLE <%al>
 and $0x0F, %al
 HEX_NIBBLE <%ah>
.endm

.macro PRINT_CHAR c=$0x20
 push %ax
 mov \c, %al
 mov $0x0E, %ah
 int $0x10
 pop %ax

.endm

.macro PRINT_HEX reg=<%al>
 push %ax
 HEX <\reg>
 PRINT_CHAR <%al>
 PRINT_CHAR <%ah>
 pop %ax
.endm

.macro RESET_DISK

 LOCAL error,end

 mov $0x00, %ah
 mov $0x80, %dl
 int $0x13

 jmp end
end:
.endm



.macro STAGE2

 LOCAL read_error, end

 RESET_DISK

 mov $__stage2_nsectors, %al
 mov $0x9000, %ebp
 mov %ebp, %esp
 mov $0x02, %ah
 mov $0x0002, %cx
 mov $0x80, %dl
 mov $0x00, %dh
 mov $0x1000, %bx


 int $0x13
 jc read_error
 jmp 1f


read_error:
 PRINT_STRING $read_fail


 .section .stage2
1:
 jmp *(0x1000)
.endm



.macro PROTECTED_MODE



 .equ CODE_SEG, 8
 .equ DATA_SEG, gdt_data - gdt_start

 cli
 lgdt gdt_descriptor
 mov %cr0, %eax
 orl $0x01, %eax
 mov %eax, %cr0

 ljmp $CODE_SEG, $protected_mode

gdt_start:
gdt_null:
 .long 0x00
 .long 0x00

gdt_code:
 .word 0xFFFF
 .word 0x0000
 .byte 0x00
 .byte 0b10011010
# 220 "header.h"
 .byte 0b11001111
# 230 "header.h"
 .byte 0x00

gdt_data:
 .word 0xffff
 .word 0x00
 .byte 0x00
 .byte 0b10010010
 .byte 0b11001111
 .byte 0x00
gdt_end:
gdt_descriptor:
 .word gdt_end - gdt_start
 .long gdt_start


.code32
protected_mode:
 mov $DATA_SEG, %ax
 mov %ax, %ds
 mov %ax, %es
 mov %ax, %fs
 mov %ax, %gs
 mov %ax, %ss

 mov $0x9000, %ebp
 mov %ebp, %esp


.endm


vga_current_line:
 .long 0

.macro VGA_PRINT_STR str
 LOCAL loop,end

 PUSH_EA

 mov \str, %ecx
 mov vga_current_line, %eax

 mov $0, %edx
 mov $25, %ebx
 div %ebx
 mov %edx, %eax
 mov $160, %edx
 mul %edx


 lea 0xb8000(%eax), %edx
 mov $0x0f, %ah


loop:
 mov (%ecx), %al
 cmp $0, %al
 je end

 mov %ax, (%edx)
 inc %ecx
 addl $2, %edx
 jmp loop


end:
 POP_EA
 incl vga_current_line

.endm
# 2 "boot.S" 2


.section .text

 BEGIN
 CLEAR
 STAGE2
 PROTECTED_MODE
 VGA_PRINT_STR $str
 jmp .

str:
 .asciz "Hello"

生成文件

.POSIX:

IMAGE ?= $(FILENAME)
LD ?= ld
LD_SCRIPT ?= linker.ld
HEADER ?=header.h
GAS ?= gcc
CFLAGS ?= -c
QEMU ?= qemu-system-i386
OUT_EXT ?= .bin


all: $(IMAGE)$(OUT_EXT)

$(IMAGE).bin: $(IMAGE).o
    $(LD) -T'$(LD_SCRIPT)' --oformat=binary '$<' -o '$@'

$(IMAGE).o : $(IMAGE).S $(HEADER) 
    $(GAS) -c '$<' -o '$@'

run: $(IMAGE)$(OUT_EXT)
    $(QEMU) '$<'

clean: 
    rm *.o *bin

链接器.ld


OUTPUT_FORMAT("elf32_i386");
SECTIONS
{
    . = 0x7c00;
    .text : {
        __start = .;
        *(.text)

        . = 0x1FE;
        SHORT(0xaa55);

        *(.stage2 )

        __stage2_nsectors = ABSOLUTE((. - __start)/512);

        . = ALIGN(512);
        __end = . ;
        __end_align_4k = ALIGN(4K);
    }
}

我正在使用 qemu 作为模拟器。在 Qemu 中，应该显示“Hello”，但这是输出。 qemu 中的输出

我无法解决这个问题。对此问题的任何指示表示赞赏。

标签： assemblyx86bootloadergnu-assemblerosdev

解决方案

可能不是你唯一的问题，但你POP_EA会以相反的顺序从你的PUSH_EA宏中弹出东西（堆栈是后进先出的），所以不会匹配：

.macro PUSH_EA
 push %eax
 push %ebx
 push %ecx
 push %edx
.endm

.macro POP_EA
 pop %eax
 pop %ebx
 pop %ecx
 pop %edx
.endm

因为最后推送的是 %edx 而第一个 pop 是 %eax，所以你最终交换了它们。弹出需要以相反的顺序：

.macro POP_EA
 pop %edx
 pop %ecx
 pop %ebx
 pop %eax
.endm

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