时间戳

首页 > 解决方案 > 如果在函数中根据 id

javascript - 如果在函数中根据 id

问题描述

我希望playSound()函数根据id选择的（悬停的）图像来完成它的工作。我尝试过的任何事情都没有成功，所以我需要全力帮助。

代码：

var sound1 = document.getElementById("audio1");
var sound2 = document.getElementById("audio2");

function playSound() {
  //if hovered image has id="x", do this
  sound1.play();

  //if hovered image has id="y", do this
  sound2.play();
}
<a href="Okokoska.html"><img src="Pkokoska.jpg" id="x" onmouseover="playSound()" onmouseout="stop()"></a>
<a href="Okonj.html"><img src="Pkonj.jpg" id="y" onmouseover="playSound()" onmouseout="stop()"></a>

<audio id="audio1"><source src="Zkokoska.wav"></audio>
<audio id="audio2"><source src="Zkrava.wav"></audio>

标签： javascripthtml

解决方案

您可以添加this到onmouseover="playSound(this)"，这将传递一个悬停的元素。

然后你在函数中捕获它：

function playSound(e) {

并用来保存id，然后只做if语句。

let id = e.id;


var sound1 = document.getElementById("audio1");
var sound2 = document.getElementById("audio2");

function playSound(e) {
  console.clear();
  console.log(e.id);
  let id = e.id;

  if (id === "x") {
    //if hovered image has id="x", do this
    sound1.play();
     console.log("Playing sound x");
  } else if (id === "y") {
    //if hovered image has id="y", do this
    sound2.play();
    console.log("Playing sound y");
  }

}
<a href="Okokoska.html"><img src="Pkokoska.jpg" id="x" onmouseover="playSound(this)" onmouseout="stop()"></a>
<a href="Okonj.html"><img src="Pkonj.jpg" id="y" onmouseover="playSound(this)" onmouseout="stop()"></a>

<audio id="audio1"><source src="Zkokoska.wav"></audio>
<audio id="audio2"><source src="Zkrava.wav"></audio>

推荐阅读