首页 > 解决方案 > 颤振:警告数据库已被锁定为 0:00:10.000000。在安卓上

问题描述

我在这个错误上停留了一个月,我无法通过谷歌找到任何解决方案。我构建了一个需要在线和离线工作的聊天应用程序,后端是 NodeJS 下面的代码是向目标设备发送任何仍待处理的消息

  async function _worker(socket) {
    console.log('worker running...')
    await connect.then(async (db) => {

        // When user A sent message to user B but user B is offline so server need to sync this message to user B
        Message.find({ isDeliver: 0 }).then(async (m) => {
            if (m.length > 0) {
                for (let i = 0; i < m.length; i++) {
                    let sender = m[i].sender;
                    let receiver = m[i].receiver;
                    let online = await checkUserOnline(socket, receiver);
                    if (online) {
                        let to_user_socket_id = getSocketIDfromMapForthisUser(`${receiver}`)
                        sendToConnectedSocket(socket, to_user_socket_id, "send_message_to_device", m[i]);
                    }
                }
            }
        });

         // When user A sent a message to user B and user B is offline but when user B is online and message delivered to user B and user A is offline server need to sync this message status to update for user A
         Message.find({ isDeliver: 1 }).then(async (m) => {
            if (m.length > 0) {
                for (let i = 0; i < m.length; i++) {
                    let sender = m[i].sender;
                    let receiver = m[i].receiver;
                    let online = await checkUserOnline(socket, sender);
                    if (online) {
                        let to_user_socket_id = getSocketIDfromMapForthisUser(`${sender}`)
                        sendToConnectedSocket(socket, to_user_socket_id, "send_message_deliver", m[i]);
                    }
                }
            }
        });

        // When user A sent a message to user B and user B is offline but when user B is online and read the message and user A is offline server need to sync this message status to update for user A
        Message.find({ isRead: 1 }).then(async (m) => {
            if (m.length > 0) {
                for (let i = 0; i < m.length; i++) {
                    let sender = m[i].sender;
                    let receiver = m[i].receiver;
                    let online = await checkUserOnline(socket, sender);
                    if (online) {
                        let to_user_socket_id = getSocketIDfromMapForthisUser(`${sender}`)
                        sendToConnectedSocket(socket, to_user_socket_id, "send_message_read", m[i]);
                    }
                }
            }
        });

    });
 }

以下是处理来自服务器的事件的方法:

插座

setOnServerSendDeliver(Function  onServerSendDeliver) {
    _socket.on('send_message_deliver', (data) {
        onServerSendDeliver(data);
    });
  }

  setOnServerSendRead(Function  onServerSendRead) {
    _socket.on('send_message_read', (data) {
      onServerSendRead(data);
    });
  }

  setOnServerSendToDevice(Function onServerSendToDevice) {
    _socket.on('send_message_to_device', (data) {
      onServerSendToDevice(data);
    });
  }

方法

 onServerSendDeliver(data) async {
    MessageModel message = MessageModel.fromJson(jsonDecode(data));
    await G.dbService.updateDeliver(message);
    G.socketUtils.sendDeliveryDone(message, new UserModel(id: message.sender));
    refreshMessage();
  }

  onServerSendRead(data) async {
    MessageModel message = MessageModel.fromJson(jsonDecode(data));
    await G.dbService.updateRead(message.chatId);
    G.socketUtils.sendReadDone(message, new UserModel(id: message.sender));
    refreshMessage();
  }

  onServerSendToDevice(data) async {
    MessageModel message = MessageModel.fromJson(jsonDecode(data));
    ChatModel chat = new ChatModel();
    chat.id = message.chatId;
    chat.fromId = message.sender;
    chat.toId = message.receiver;
    chat.message = message.content;
    await G.dbService.chatOperation(chat);
    await G.dbService.insertMessage(message);
    await G.dbService.updateDeliver(message);
    G.socketUtils.sendDelivery(message, new UserModel(id: message.sender));
    refreshMessage();
  } 

在我设置的服务器中

setInterval(_worker, 1500, socket);

加载检查消息并发送到终端设备

和我的数据库功能

Future<String> updateRead(String chatId) async {
    Database db = await database;
    try {
      await db.transaction((txn) async {
        return await txn.rawUpdate(
            "UPDATE messages SET isRead = 1, isSend = 1, isDeliver = 1 WHERE chatId = ? AND status = 0",
            [chatId]);
      });

      await db.transaction((txn) async {
        return await txn.rawUpdate(
            "UPDATE chats SET isRead = 1, isSend = 1, isDeliver = 1 WHERE id = ? AND status = 0",
            [chatId]);
      });
    } catch (e) {
      print(e.toString());
    }
    return chatId;
  }

  Future<String> updateDeliver(MessageModel message) async {
    Database db = await database;
    String id;
    try {
      id = message.id;
      await db.transaction((txn) async {
        return await txn.rawUpdate(
            "UPDATE messages SET isDeliver = 1 WHERE id = ? AND status = 0",
            [message.id]);
      });

      await db.transaction((txn) async {
        return await txn.rawUpdate(
            "UPDATE chats SET isDeliver = 1 WHERE id = ? AND status = 0",
            [message.chatId]);
      });
    } catch (e) {
      print(e.toString());
    }
    return id;
  } 

iOS 工作正常,但在 android 上我总是遇到这个错误,我的应用程序卡住了:

颤振:警告数据库已被锁定为 0:00:10.000000。确保在事务期间始终使用事务对象进行数据库操作

任何帮助都是合适的

更新

我试图将数据库函数修改为:

Future<String> updateDeliver(MessageModel message) async {
    Database db = await database;
    String id;
    try {
      id = message.id;
      await db.transaction((txn) async {
        var batch = txn.batch();
        batch.rawUpdate(
            "UPDATE messages SET isDeliver = 1 WHERE id = ? AND status = 0",
            [message.id]);
        batch.rawUpdate(
            "UPDATE chats SET isDeliver = 1 WHERE id = ? AND status = 0",
            [message.chatId]);
        batch.commit();
      });
    } catch (e) {
      print(e.toString());
    }
    return id;
  }

但我仍然面临同样的问题

标签: sqlitefluttersqflite

解决方案


确保await事务中的任何异步方法:

await batch.commit();

当您忘记此类await.

是的,不要为单个操作创建事务并尝试对事务中的操作进行分组(如果可以的话,也可以进行批处理)。

您还可以打开日志记录以确保您没有执行过多的 sqlite 查询。


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