regex - 跳过包含在我正在寻找的模式中的正则表达式模式

Question

我正在解析包含以 开头^[和结尾的脚注的 Pandoc-markdown 文件，]其中一些包含嵌入的[]. 例如：

...
to explain how the feature came to be as it is, so you can use generics more
effectively.^[Angelika Langer's [Java Generics FAQ](
www.angelikalanger.com/GenericsFAQ/JavaGenericsFAQ.html) as well as her other
writings (together with Klaus Kreft) were invaluable during the preparation of
this chapter.]
...

（在 Python 中）的简单方法：

re.compile(r"\^\[.+?\]", flags=re.DOTALL)

一开始就停止，]因此没有捕获整个脚注。有没有办法通过嵌套[]子句？

标签： regex

Answer 1

您可以使用 PyPi 正则表达式模块使用子程序来做到这一点，您只需要在设置组边界时小心：

import regex
text = r"""...
to explain how the feature came to be as it is, so you can use generics more
effectively.^[Angelika Langer's [Java Generics FAQ](
www.angelikalanger.com/GenericsFAQ/JavaGenericsFAQ.html) as well as her other
writings (together with Klaus Kreft) were invaluable during the preparation of
this chapter.]
..."""
print( [x.group(1) for x in regex.finditer(r'\^(\[(?:[^][]++|(?1))*])', text)] )

输出：

["[Angelika Langer's [Java Generics FAQ](\nwww.angelikalanger.com/GenericsFAQ/JavaGenericsFAQ.html) as well as her other\nwritings (together with Klaus Kreft) were invaluable during the preparation of\nthis chapter.]"]

请参阅Python 演示和正则表达式演示。细节：

• \^-^字符
• (\[(?:[^][]++|(?1))*])- 第 1 组：
  • \[- 一个[字符
  • (?:[^][]++|(?1))*- 0 次或多次出现：
    • [^][]++]- 除了and之外的一个或多个字符[
    • |- 或者
    • (?1)- 第 1 组模式
• ]- 一个]字符。