python - 如何在while循环或if语句中打印出下一年

Question

我目前正在自己​​做一个在线练习课程。这是我到目前为止的代码。该代码仅正确打印出其中一种条件。if 跳跃条件打印出两个打印语句。我如何让 if 跳跃只打印出一个语句并忽略它之后的内容。

inp_year = int(input("Give year:"))
  
year = inp_year

leap = year % 4 == 0 and year %100 != 0 or year % 100 == 0 and year % 400 ==0

if leap:
    print("The next leap year from",year,"is",year + 4)
    
while not leap:
    year += 1
    leap = year % 4 == 0 and year %100 != 0 or year % 100 == 0 and year % 400 ==0

print("The next leap year from",inp_year,"is",year)

标签： pythonif-statementwhile-loopleap-year

Answer 1

您可以尝试使用这样的 else 语句：

if leap:
    # Code to run when leap is True
    print("The next leap year from",year,"is",year + 4)

else:
    # Your other code to run when leap is False
    while not leap:
        year += 1

        leap = year % 4 == 0 and year %100 != 0 or year % 100 == 0 and year % 400 ==0

    print("The next leap year from",inp_year,"is",year)

如果条件为 True，则该if语句运行其中缩进的代码。同样，您可以在elif之后使用语句if来检查其他条件。最后，如果前面的和条件都不为真，则该else语句运行其中的代码。ifelif