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python - 使用 for 循环和 group by 计算百分比

问题描述

如果我有以下带有循环的代码，它根据下面给出了输赢类型的比率，如果我想查看相同的数据但按教授分组，我将如何更改代码？

leads = ['Passed','Failed']
max_status = None
max_percent = None
for lead in leads:
    df_overall = df[(df['Status']== lead) & (df['size']== '20-34')]
    num_overall = len(df_overall) 
    lead_df = df[(df['size']== '20-34')]
    num_total = len(lead_df)
    percentage_overall = num_overall / num_total
   
    
    if max_status is None: 
        
        
        
        print(lead, percentage_overall)

这给了我如下输出：

Passed .65
Failed .35

我想编辑按教授分组的代码，因为它们也是我数据框中的教授列。

预期输出：

Mr. Johnson Passed .35
Mr. Johnson Failed .65
Ms. Jones   Passed .90
Ms. Jones   Failed .10
Mr. Boe     Passed .80
Mr. Boe     Passed .20

谢谢

标签： pythonpython-3.xpandas

解决方案

我相信你需要GroupBy.size：

leads = ['Passed','Failed']

lead_df = df[(df['size']== '20-34')]
#filter by list leads
df_overall = lead_df[lead_df['Status'].isin(lead)]

num_overall1 = df_overall.groupby(['professor','Status']).size()
num_total1 = lead_df.groupby(['professor','Status']).size()

out = num_overall1.div(num_total1).reset_index(name='per')
print (out)

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