首页 > 解决方案 > 根据条件更改文本颜色

问题描述

是否有根据条件更改文本颜色的示例?例如,我想在$hasil>=80它变成绿色、$hasil>=70黄色和下面是红色的时候做出条件。

这是我的逻辑代码


while ($data = mysqli_fetch_assoc($result))
{
    $n1 = ($data["nilai_output"]) * 0.7;
    $n2 = ($data["nilai_atasan"]) * 0.1;
    $n3 = ($data["nilai_learning"]) * 0.1;
    $n4 = ($data["nilai_kedisiplinan"]) * 0.05;
    $n5 = ($data["nilai_5r"]) * 0.05;

    $hasil = ($n1 + $n2 + $n3 + $n4 + $n5);

    if ($hasil >= 95)
    {
        $grade = 1.25;
        $ikk = "istemewa";
    }
    elseif ($hasil >= 90)
    {
        $grade = 1.10;
        $ikk = "Sangat Memuaskan";
    }
    elseif ($hasil >= 85)
    {
        $grade = 1.00;
        $ikk = "Memuaskan";
    }
    elseif ($hasil >= 80)
    {
        $grade = 0.90;
        $ikk = "Cukup Memuaskan";
    }
    elseif ($hasil >= 75)
    {
        $grade = 0.75;
        $ikk = "Memadai";
    }
    elseif ($hasil >= 70)
    {
        $grade = 0.50;
        $ikk = "Kurang Memadai";
    }
    elseif ($hasil >= 1)
    {
        $grade = 0.25;
        $ikk = "Tidak Memadai";
    }
    else
    {
        $ikk = "Tidak Berkontribusi";
    }

    $no++;   

这是我的表格列

  <td class="font-weight-bold text-danger"><?php echo $hasil;?></td>
  <td class="font-weight-bold text-danger"><?php echo $grade;?></td>
  <td class="font-weight-bold text-danger"><?php echo $ikk;?></td>

我希望这三列使用颜色条件谢谢

标签: phphtmlforms

解决方案


像这样试试

if ($hasil >= 80) {
  $grade = 0.90;
  $color = 'green';
  $ikk = "Cukup Memuaskan";
}elseif($hasil >= 70 && $hasil < 80 ) {
  $grade = 0.75;
  $color = 'yellow';
  $ikk = "Memadai";
}elseif($hasil >= 1 && $hasil < 70 ) {
  $grade = 0.50;
  $color = 'red';
  $ikk = "Kurang Memadai";
}else{
  $ikk = "Tidak Berkontribusi";
}


<td class="font-weight-bold text-danger" style="color:<?=$color;?>"><?php echo $hasil;?></td>

我希望这对你有帮助!


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