python - 列出独特的元素，保持顺序。只记住刚刚看到的元素

Question

我有一个（嵌套元组的）列表，我想消除与元素具有相同第一项和最后一项的嵌套元组， 保留顺序：

my_list = [('0.5', '00', '0-0'),
 ('0.75', '02', '0-0'),
 ('0.5', '02', '0-0'),
 ('0.75', '02', '0-0'),
 ('0.75', '03', '0-0'),
 ('0.75', '04', '0-0'),
 ('0.75', '05', '0-0'),
 ('0.75', '06', '0-0'),
 ('0.75', '07', '0-0'),
 ('0.75', '08', '0-0'),
 ('0.75', '09', '0-0'),
 ('0.75', '10', '0-0'),
 ('0.75', '11', '0-0'),
 ('0.75', '13', '0-0'),
 ('0.75', '14', '0-0'),
 ('0.5', '15', '0-0'),
 ('0.75', '15', '0-0'),
 ('0.5', '15', '0-0')]

这是我需要的输出：

[('0.5', '00', '0-0'),
 ('0.75', '02', '0-0'),
 ('0.5', '02', '0-0'),
 ('0.75', '02', '0-0'),
 ('0.5', '15', '0-0'),
 ('0.75', '15', '0-0'),
 ('0.5', '15', '0-0')]

我试过这个但没有奏效：

from more_itertools import unique_justseen

list(unique_justseen(my_list))

标签： python

Answer 1

在追加之前检查元素与先前追加的元素：

out = []
for el in my_list:
    if not out or el[0] != out[-1][0] or el[-1] != out[-1][-1]:
        out.append(el)

print(out)

给

[('0.5', '00', '0-0'), ('0.75', '02', '0-0'), ('0.5', '02', '0-0'), ('0.75', '02', '0-0'), ('0.5', '15', '0-0'), ('0.75', '15', '0-0'), ('0.5', '15', '0-0')]