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c++ - Linux API 读/写和 c++ 位集

问题描述

如何使用具有 Linux API 读/写功能的 C++ 位集容器？

像这样的东西：

#include <vector>
#include <bitset>

#include <fcntl.h>      // Linux API open
#include <unistd.h>     // Linux API read,write,close

using namespace std;

int main() {
    // Some 8-bit register of some device
    // Using vector for read and write operations.
    // Using bitset to manipulate individual bits.
    vector<bitset<8>> control_register;
    
    // Set bit 1 of control_register to 1 (true).
    control_register[0].set(1);
    
    // Open new file for writing (create file)
    int fd = 0;
    const char *path = "./test.txt";
    fd = (open(path, O_WRONLY | O_CREAT | O_TRUNC, S_IRWXU));
    
    // Write to file from vector (using Linux API)
    write(fd, control_register.data(), control_register.size());
    
    // close file
    close(fd);
    
    return 0;
}

我们可以不使用向量容器而立即编写位集吗？

标签： c++linuxserializationstd-bitset

解决方案

您可以做的是，std::bitset在写入数据之前转换为 a 。就像是

std::bitset<8> controlRegister = 0b00101100; // Use some consts and combine them 
                                             // with bitwise or (|) to make this more 
                                             // human readable
uint8_t ctrl = static_cast<uint8_t>(controlRegister.to_ulong() & 0xFF);

write(fd, &ctrl , 1);

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