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python - Selenium 帮助切换到 iframe 然后点击链接

问题描述

我目前正在尝试单击每个链接，这些链接会为我提供有关餐厅的更多信息。 https://www.halton.ca/For-Residents/Food-Safety/Dinewise/Search-Directory-of-Food-Premises-Dinewise。

第一家餐厅是 151 Social，我试图点击它，但似乎不适合我。我已经编译了一个 pd.Series 包含每个餐厅的 xpath 链接

//*[@id="lblContent"]/div[3]/table/tbody/tr[1]/td[1]/a

那只是第一家餐厅

for element in range(len(df['Temp xPath links'])):    
    frame = WebDriverWait(driver, 30).until(EC.frame_to_be_available_and_switch_to_it((By.ID,"iframe-form")))
    ref = WebDriverWait(driver, 30).until(EC.presence_of_element_located(By.xpath(df['Temp xPath links'][element])))
    driver.execute_script("arguments[0].scrollIntoView();", ref)
    driver.execute_script("arguments[0].click();", ref)

我正在努力进入下一页。任何帮助都会很棒。

标签： pythonseleniumweb-scraping

解决方案

诱导WebdriverWait() 并等待element_to_be_clickable() 和XPATH

WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH,"//a[text()='151 Social']"))).click()

完整代码：

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

driver = webdriver.Chrome()
driver.get("https://www.halton.ca/For-Residents/Food-Safety/Dinewise/Search-Directory-of-Food-Premises-Dinewise")
WebDriverWait(driver,10).until(EC.frame_to_be_available_and_switch_to_it((By.ID,"iframe-form")))
WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.ID,"btnOK"))).click()
WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.ID,"btnGetEstablishments"))).click()
WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH,"//a[text()='151 Social']"))).click()

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