python-3.x - Discord.py 重写 Modmail 系统
问题描述
几乎我正在尝试为服务器制作一个 modmail 机器人。这是代码。
@client.event
async def on_message(message):
modmail_channel = discord.utils.get(client.get_all_channels(), name="bot-log")
if message.author == client.user:
return
if str(message.channel.type) == "private":
embed = discord.Embed(color=0x00FFFF)
embed.set_author(name=f"Olympia Gaming Modmail System", icon_url="https://cdn.discordapp.com/icons/690937143522099220/34fbd058360c3d4696848592ff1c5191.webp?size=1024")
embed.add_field(name='Report a member:', value=f"React with 1️⃣ if you want to report a member.")
embed.add_field(name='Report a Staff Member:', value=f"React with 2️⃣ if you want to report a Staff Member.")
embed.add_field(name='Warn Appeal:', value=f"React with 3️⃣ if you would like to appeal a warning.")
embed.add_field(name='Question:', value=f"React with 4️⃣ if you have a question about our moderation system or the server rules.")
embed.set_footer(text="Olympia Gaming | Modmail")
msg = await message.author.send(embed=embed)
await msg.add_reaction("1️⃣")
await msg.add_reaction("2️⃣")
await msg.add_reaction("3️⃣")
await msg.add_reaction("4️⃣")
def check(reaction, user):
return user == message.author and str(reaction.emoji) in ["1️⃣", "2️⃣", "3️⃣", "4️⃣"]
while True:
try:
reaction, user = await client.wait_for("reaction_add", timeout=60, check=check)
if str(reaction.emoji) == "1️⃣":
embed = discord.Embed(color=0x00FFFF)
embed.set_author(name=f"Olympia Gaming Modmail System", icon_url="https://cdn.discordapp.com/icons/690937143522099220/34fbd058360c3d4696848592ff1c5191.webp?size=1024")
embed.add_field(name='How to Report:', value="Send the ID of the person you are reporting and attach add a screen shot of them breaking a rule (can be ToS or a server rule).")
embed.set_footer(text="Olympia Gaming | Report a member ")
await message.author.send(embed=embed)
message, user = await client.wait_for("on_message", timeout=60, check=check)
embed = discord.Embed(title=f"{message.content}", color=0x00FFFF)
await modmail_channel.send(embed=embed)
except asyncio.TimeoutError:
await message.delete()
break
此代码的唯一问题是它不会将消息发送到 modmail 通道,并且会不断重复原始消息。有人可以解释我如何解决这个问题吗?
解决方案
我有几个建议给你。
首先,我强烈建议您将以下内容作为您的第一条语句on_message
:
if message.guild:
return
这将替换您的if str(message.channel.type) == "private":
,并确保任何未在 DM 中发送的消息都会立即被丢弃。
其次,我建议使用get_channel而不是你的discord.utils.get(client.get_all_channels(), name="bot-log")
,它将搜索你的机器人所在的每个频道,直到找到一个名为 的频道bot-log
。这是低效的。
现在,您的机器人每次都会发送初始消息的原因是因为每次向机器人发送消息时on_message
都会调用 main。您将需要跟踪哪些用户已经收到了初始消息,这样您就不会再次发送它。最简单的实现就是添加用户 ID 的列表,然后在 main 中检查该列表on_message
。
此外,您的第二个wait_for
不起作用,它应该只是“消息”并且您正在使用您的第一个检查功能,该功能正在寻找反应。
这一下子就很多了,所以这里是我on_message
的全部更改,希望你不要只是复制粘贴它而不学习任何东西:
sent_users = []
@client.event
async def on_message(message):
if message.guild: # ensure the channel is a DM
return
if message.author == client.user:
return
if message.author.id in sent_users: # Ensure the intial message hasn't been sent before
return
modmail_channel = client.get_channel(CHANNEL_ID)
embed = discord.Embed(color=0x00FFFF)
embed.set_author(name=f"Olympia Gaming Modmail System", icon_url="https://cdn.discordapp.com/icons/690937143522099220/34fbd058360c3d4696848592ff1c5191.webp?size=1024")
embed.add_field(name='Report a member:', value=f"React with 1️⃣ if you want to report a member.")
embed.add_field(name='Report a Staff Member:', value=f"React with 2️⃣ if you want to report a Staff Member.")
embed.add_field(name='Warn Appeal:', value=f"React with 3️⃣ if you would like to appeal a warning.")
embed.add_field(name='Question:', value=f"React with 4️⃣ if you have a question about our moderation system or the server rules.")
embed.set_footer(text="Olympia Gaming | Modmail")
msg = await message.author.send(embed=embed)
await msg.add_reaction("1️⃣")
await msg.add_reaction("2️⃣")
await msg.add_reaction("3️⃣")
await msg.add_reaction("4️⃣")
sent_users.append(message.author.id) # add this user to the list of sent users
try:
def check(reaction, user):
return user == message.author and str(reaction.emoji) in ["1️⃣", "2️⃣", "3️⃣", "4️⃣"]
reaction, user = await client.wait_for("reaction_add", timeout=60, check=check)
if str(reaction.emoji) == "1️⃣":
embed = discord.Embed(color=0x00FFFF)
embed.set_author(name=f"Olympia Gaming Modmail System", icon_url="https://cdn.discordapp.com/icons/690937143522099220/34fbd058360c3d4696848592ff1c5191.webp?size=1024")
embed.add_field(name='How to Report:', value="Send the ID of the person you are reporting and attach add a screen shot of them breaking a rule (can be ToS or a server rule).")
embed.set_footer(text="Olympia Gaming | Report a member ")
await message.author.send(embed=embed)
message = await client.wait_for("message", timeout=60, check=lambda m: m.channel == message.channel and m.author == message.author)
embed = discord.Embed(title=f"{message.content}", color=0x00FFFF)
await modmail_channel.send(embed=embed)
except asyncio.TimeoutError:
await message.delete()
推荐阅读
- azure - 如何从 Azure API 管理“发送请求”登录到 App Insights
- react-native - 在另一个屏幕中反应原生使用状态
- c# - 为什么我在转换为 int 时会从字符串中得到错误的值
- json - Azure - Geosearch - 返回距离
- java - 根据规范,在以毫秒为单位的日期上,evaluatePreconditions 的正确行为是什么?
- reactjs - React 如何破坏构造函数中的深层道具?
- python - 计算有多少不同的单词恰好有两次字母“o”
- javascript - 为什么 eslint 考虑 JSX 或一些反应 @types undefined,因为将 typescript-eslint/parser 升级到版本 4.0.0
- google-apps-script - 如何在 Data Studio 中使用 GraphQL 等库?
- ios - 为什么我在钥匙串中看不到我保存的登录名/密码?