首页 > 解决方案 > 如何更新哈希属性,更新 Perl Moose 中的其他哈希属性

问题描述

这里 hash2 属性依赖于 hash1。事实上,hash2 是由 hash1 驱动的。例如,

hash1 -> key1 => value1, key2 => value2 等等。

hash2 -> key1 => 6, key2 => 6 等它是长度(来自 hash1 的值,去 hash2)

尝试了类似下面的方法,但没有帮助。

has 'hash1' => (
    is        => 'rw',
    isa       => 'HashRef[Str]',
    default   => sub { {} },
    handles   => {
        map { $_ . '_hash1' => $_ } @hash_delegations
    },
);

has 'hash2' => (
    is        => 'rw',
    isa       => 'HashRef',
    builder   => '_filter_hash1',
    handles   => {
        map { $_ . 'hash2' => $_ } @hash_delegations
    },
);

sub _filter_hash1 {
    my $self = shift;
    for my $alias ($self->keys_hash1()) {
        return {$alias, length($alias)};
    }
}

Hash1 将随着时间的推移而设置,不确定如何确保我应该如何捕获 hash1 上的事件以更新 hash2 中的条目。知道如何实现这一目标吗?

标签: perlmoose

解决方案


您是否正在尝试创建值长度的缓存?实际上,长度是如此之快,您不需要缓存它,但它可能只是更复杂事物的简化示例。我会使用触发器,加上第一个哈希的特征来强制通过方法设置值。直接更改哈希值不会触发其他属性的更改。

#!/usr/bin/perl
use warnings;
use strict;
use feature qw{ say };

{   package My::Object;
    use Moose;

    my @hash_delegations = qw( keys );

    has 'hash1' => (
        is      => 'rw',
        isa     => 'HashRef[Str]',
        default => sub { {} },
        trigger => \&_update_hash2,
        traits  => ['Hash'],
        handles => { set_hash1 => 'set' },
    );

    has 'hash2' => (
        is     => 'ro',
        writer => '_set_hash2',
        isa    => 'HashRef',
    );

    sub _update_hash2 {
        my ($self, $new, $old) = @_;
        $self->_set_hash2({ map { $_ => length $self->hash1->{$_} }
                            keys %{ $self->hash1 }});
    }
}

my $o = 'My::Object'->new(hash1 => {a => 42, b => 'Universe'});
say $o->hash2->{$_} for qw( a b );

$o->set_hash1(c => '0123456789');
say $o->hash2->{c};

$o->hash1->{c} = "";  # Wrong!
say $o->hash2->{c};   # Didn't change :-(

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