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python - python随机函数为两个不同的实例生成相同的值

问题描述

因此，对于我正在编写的这段代码，我试图为三个不同的玩家生成一组三张随机牌，其中一个是人类，两个是模拟的。为此，我正在使用此代码。

def shuffle_p1():
    p_1_human_card_1=random.randint(1,3)
    p_1_human_card_2=random.randint(1,3)
    p_1_human_card_3=random.randint(1,3)
    p_1_human_cards=[p_1_human_card_1,p_1_human_card_2,p_1_human_card_3]

    return (p_1_human_cards)


def shuffle_p2():
    p_2_ai_card_1=random.randint(1,3)
    p_2_ai_card_2=random.randint(1,3)
    p_2_ai_card_3=random.randint(1,3)
    p_2_ai_cards=[p_2_ai_card_1,p_2_ai_card_2,p_2_ai_card_3]

    return (p_1_human_cards)


def shuffle_p3():
    p_3_ai_card_1=random.randint(1,3)
    p_3_ai_card_2=random.randint(1,3)
    p_3_ai_card_3=random.randint(1,3)
    p_3_ai_cards=[p_3_ai_card_1,p_3_ai_card_2,p_3_ai_card_3]

    return (p_1_human_cards)

p_1_human_cards=shuffle_p1()
p_2_ai_cards=shuffle_p2()
p_3_ai_cards=shuffle_p3()

这会生成三组，但玩家 1 和玩家 2 每次都拥有完全相同的牌。我什至放了一组不同的代码

def card_auth_p1():
    while p_1_human_cards[0]==p_1_human_cards[1] or p_1_human_cards[0]==p_1_human_cards[2]:
        p_1_human_cards[0]=random.randint(1,3)
    while p_1_human_cards[1]==p_1_human_cards[0] or p_1_human_cards[1]==p_1_human_cards[2]:
        p_1_human_cards[1]=random.randint(1,3)

def card_auth_p2():
    while p_2_ai_cards[0]==p_2_ai_cards[1] or p_2_ai_cards[0]==p_2_ai_cards[2]:
        p_2_ai_cards[0]=random.randint(1,3)
    while p_2_ai_cards[1]==p_2_ai_cards[0] or p_2_ai_cards[1]==p_2_ai_cards[2]:
        p_2_ai_cards[1]=random.randint(1,3)

def card_auth_p3():
    while p_3_ai_cards[0]==p_3_ai_cards[1] or p_3_ai_cards[0]==p_3_ai_cards[2]:
        p_3_ai_cards[0]=random.randint(1,3)
    while p_3_ai_cards[1]==p_3_ai_cards[0] or p_3_ai_cards[1]==p_3_ai_cards[2]:
        p_3_ai_cards[1]=random.randint(1,3)

并且

if p_1_human_cards == p_2_ai_cards or p_1_human_cards == p_3_ai_cards:
    p_1_human_cards=shuffle_p1()

if p_2_ai_cards == p_1_human_cards or p_2_ai_cards == p_3_ai_cards:
    p_2_ai_cards=shuffle_p2()

if p_3_ai_cards == p_1_human_cards or p_2_ai_cards == p_3_ai_cards:
    p_3_ai_cards=shuffle_p3()

确保它们不完全相同，但打印三个列表显示玩家 1 和 2 仍然相同。此外，即使在使用此代码在三组之间随机交易的第四个代码块之后

def card_trade():
    print('Round 1')
    p_1_choice=int(input('pick the card you want to take from player 2'))
    while p_1_choice<1 or p_1_choice>3:
        print('pick between 1 and 3')
        p_1_choice=int(input('pick the card you want to take from player 2'))

    if p_1_choice==1:
       p_1_extra_card=p_2_ai_cards[0]
       p_2_ai_cards.remove(p_2_ai_cards[0])

    elif p_1_choice==2:
       p_1_extra_card=p_2_ai_cards[1]
       p_2_ai_cards.remove(p_2_ai_cards[1])

    elif p_1_choice==3:
       p_1_extra_card=p_2_ai_cards[2]
       p_2_ai_cards.remove(p_2_ai_cards[2])

    p_1_human_cards.append(p_1_extra_card)

    p_2_choice=random.randint(1,3)

    print('AI decided to take',p_2_choice,'from player 3')
    if p_2_choice==1:
       p_2_extra_card=p_3_ai_cards[0]
       p_3_ai_cards.remove(p_3_ai_cards[0])

    elif p_2_choice==2:
       p_2_extra_card=p_3_ai_cards[1]
       p_3_ai_cards.remove(p_3_ai_cards[1])

    elif p_2_choice==3:
       p_2_extra_card=p_3_ai_cards[2]
       p_3_ai_cards.remove(p_3_ai_cards[2])

    p_2_ai_cards.append(p_2_extra_card)

    p_3_choice=random.randint(1,4)

    print('AI decided to take',p_3_choice,'from player 1')
    if p_3_choice==1:
       p_3_extra_card=p_1_human_cards[0]
       p_1_human_cards.remove(p_1_human_cards[0])

    elif p_3_choice==2:
       p_3_extra_card=p_1_human_cards[1]
       p_1_human_cards.remove(p_1_human_cards[1])

    elif p_3_choice==3:
       p_3_extra_card=p_1_human_cards[2]
       p_1_human_cards.remove(p_1_human_cards[2])

    elif p_3_choice==3:
       p_3_extra_card=p_1_human_cards[3]
       p_1_human_cards.remove(p_1_human_cards[33])

    p_3_ai_cards.append(p_3_extra_card)

前两名球员的结局​​总是完全相同。我似乎无法弄清楚为什么它们似乎永远不会改变，并且希望有任何见解来帮助解决这个问题。

在纸牌交易（）过程中有时需要注意的另一件事是，当人类玩家选择 3 作为他们的选择时，计算机可能会抛出错误，但它的做法非常不一致，因此我也无法查明该错误的根源。

标签： pythonrandom

解决方案

如果你有 Python 3.6+，你也可以试试 secrets

try:
    import secrets as random
except ModuleNotFoundError:
    import random

# Use system resources for randomization
rnd = random.SystemRandom()

# Set available card options
AVAILABLE_CARDS = [1,2,3,]

# Set number of cards per hand.
NUMBER_OF_CARDS = 3

# Create a simple key-value collection.
players = dict(
    p_1_human_cards = None,
    p_2_ai_cards = None,
    p_3_ai_cards= None,
    )

# Define a shuffler() function.  Parameters are number of cards and available cards.
def shuffler(n_cards=NUMBER_OF_CARDS , available_cards = AVAILABLE_CARDS ):
    return tuple([rnd.choice(available_cards) for _ in range(n_cards)])

# Iterate through players to set each hand
for hand in players:
    players[hand] = shuffler()


# Print result
for player, hand in players.items():
    print(f"{player}: {hand}")

输出：

p_1_human_cards: (2, 1, 3)
p_2_ai_cards: (3, 2, 1)
p_3_ai_cards: (2, 3, 3)

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