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java - 显示 2 个数组的交集

问题描述

我正在尝试找到一种方法来显示我的 2 组包含元素的数组的交集。我找不到显示路口的方法

这是一种查找数组交集的方法

enum Month {
    
    Jan ("Janurary","01"),
    Feb ("Feburary","02"),
    Mar ("March","03"),
    Apr ("April","04"),
    May ("May","05"),
    Jun ("June","06"),
    Jul ("July","07"),
    Aug ("August","08"),
    Sep ("September","09"),
    Oct ("October","10"),
    Nov ("November","11"),
    Dec ("December","12");
    
    private final String day; //day of the month
    private final String date; //name of the date
    
    //enum constructor 
    Month(String date, String day)
    {
        this.date=date;
        this.day=day;
    }
    
    //accessor for field day
    public String getDay() {
        return day;
    }
    //accessor fpr field month
    public String getDate() {
        return date;
    }
}

class Set{
...
...
...     
public void intersection(Set otherSet)
        {
              for(int x=0; x< otherSet.s.size(); x++)
                {
                   if(belongTo(otherSet.s.get(x)))
                   {
                       addElement(otherSet.s.get(x));
                   }
                }
    }

此方法是获取数组中的一组随机元素。2个不同的类，类Set有其他方法来计算其他东西。主要类是显示它

class Test{
   ... 
   ...
   ...
    private static Set getASet()
        {
            //Set s=new Set()   
            Set s=new Set();
            int rand=(int)(Math.random()*12);
            for(int i=0;i<=rand;i++)
            {
                s.addElement(getAnElement());
            }
            return s;
            
        }
}
    private static void intersectionExample() {
            
                Set A=getASet();
                Set B=getASet();
                Set u=new Set();
                u= A.intersection(B);
                System.out.println("Given sets");
                System.out.printf("A={%s}%n", A.toString());
                System.out.printf("B={%s}%n",B.toString());
                System.out.printf("Intersection of A and B = {%s}", u.toString());
            }

标签： java

解决方案

public class Test {

    private static Integer getAnElement() {
        return (int) (Math.random() * 10);
    }

    private static Set getASet() {
        //Set s=new Set()   
        Set<Integer> s = new HashSet();
        int rand = (int) (Math.random() * 12);
        for (int i = 0; i <= rand; i++) {
            s.add(getAnElement());
        }
        return s;

    }
    
    private static Set intersection(Set A , Set B) { 
        Set<Integer> s = new HashSet();
        Iterator<Integer> it = A.iterator();
        while(it.hasNext()){
            Integer i = it.next();
            if(B.contains(i)) s.add(i);
        }
        return s;
    }

    public static void main(String[] args) {
        Set A = getASet();
        Set B = getASet();
        Set u = intersection(A, B);
        System.out.println("Given sets");
        System.out.printf("A={%s}%n", A.toString());
        System.out.printf("B={%s}%n", B.toString());
        System.out.printf("Intersection of A and B = {%s}%n", u.toString());
    }

}

输出：

Given sets
A={[0, 3, 7, 8]}
B={[0, 1, 3, 4, 6, 7, 9]}
Intersection of A and B = {[0, 3, 7]}

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