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search - 过滤器上的运算符 'and' & 'or' SuiteScript 2.0 (NetSuite)

问题描述

我需要在搜索中对过滤器设置条件。我浏览了很多论坛，但没有找到实用的解决方案。经过多次不确定的测试，我来向您寻求帮助。我的代码：

function retrieveVendor(vendorValues){

    var subsidiaryIdFilter = SEARCHMODULE.createFilter({
            name: 'internalid',
            join: 'subsidiary',
            operator: SEARCHMODULE.Operator.ANYOF,
            values: vendorValues.companyCode
    });
    var addressFilter = SEARCHMODULE.createFilter({
        name: 'address',
        join: 'vendor',
        operator: SEARCHMODULE.Operator.CONTAINS,
        values: vendorValues.street
    });
    var cityFilter = SEARCHMODULE.createFilter({
        name: 'city',
        join: 'vendor',
        operator: SEARCHMODULE.Operator.CONTAINS,
        values: vendorValues.city
    });
    var zipFilter = SEARCHMODULE.createFilter({
        name: 'zipcode',
        join: 'vendor',
        operator: SEARCHMODULE.Operator.CONTAINS,
        values: vendorValues.postalCode
    });
    
    var vendorIdTest = SEARCHMODULE.create({
        type: SEARCHMODULE.Type.VENDOR_SUBSIDIARY_RELATIONSHIP,
        columns: [
            SEARCHMODULE.createColumn({name:'entityid', join: 'vendor'}),
            SEARCHMODULE.createColumn({name:'internalid', join: 'subsidiary'}),
            SEARCHMODULE.createColumn({name:'address', join: 'vendor'})
            ],
        filters: [
            subsidiaryIdFilter, 'and', [addressFilter, 'or', zipFilter]
        ]
    });
    var nbOfResults = vendorIdTest.runPaged().count;
    var resultArray = [];

    var aa = vendorIdTest.run().each(function(result){
        var obj ={};
        obj['vendorName'] = result.getValue({
            name: 'entityid',
            join: 'vendor'
        });
        obj['idOfSubsidiary'] = result.getValue({
            name: 'internalid',
            join: 'subsidiary'
        });
        obj['vendorAddress'] = result.getValue({
            name: 'address',
            join: 'vendor'
        });
        resultArray.push(obj);
        return true;
    });
    var result = nbOfResults + ' : ' + JSON.stringify(resultArray);
    
    return result;
}

以下是在我的搜索的“过滤器”参数上尝试的所有语法：

subsidiaryIdFilter, 'and', [addressFilter, 'or', zipFilter]

[subsidiaryIdFilter, 'and', [addressFilter, 'or', zipFilter]]

subsidiaryIdFilter, 'and', (addressFilter, 'or', zipFilter)

subsidiaryIdFilter && (addressFilter, 'or', zipFilter)

subsidiaryIdFilter && (addressFilter || zipFilter)

我当然在 SuiteScript 文档中进行了搜索，但没有提到这个主题。谢谢您的帮助。

标签： searchfilternetsuitesuitescriptsuitescript2.0

解决方案

感谢插件（https://chrome.google.com/webstore/detail/netsuite-search-export/gglbgdfbkaelbjpjkiepdmfaihdokglp），我找到了在我的过滤器之间放置 AND 和 OR 的语法：

var subsidiaryIdFilter = ["subsidiary.internalid", "anyof", vendorValues.companyCode];
var addressFilter = ["vendor.addresslabel", "contains", vendorValues.street];
var cityFilter = ["vendor.city", "contains", vendorValues.city];
var vendorNameFilter = ["vendor.entityid", "contains", vendorValues.name];
var zipFilter = ["vendor.zipcode", "contains", vendorValues.postalCode];
    
var addressSearch = SEARCHMODULE.create({
        type: SEARCHMODULE.Type.VENDOR_SUBSIDIARY_RELATIONSHIP,
        columns: [
                SEARCHMODULE.createColumn({name:'entityid', join: 'vendor', sort : SEARCHMODULE.Sort.ASC})
            ],
        filters: [
            subsidiaryIdFilter, "AND", [zipFilter, "OR", cityFilter, "OR", addressFilter]
        ]
    });

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