时间戳

首页 > 解决方案 > SQL大查询脚本问题

sql - SQL大查询脚本问题

问题描述

你能帮帮我吗，我不明白我的 WHERE 有什么问题。我尝试了几件事，但无法得出正确的结论。

SELECT 
CONCAT(fullvisitorId, "-", CAST(visitstarttime AS STRING)) as session,
RANK() OVER(PARTITION BY CONCAT(fullvisitorId, "-", CAST(visitstarttime AS STRING)) ORDER BY hitNumber ASC) AS Rank, 
(SELECT MAX(cd.value) FROM hits.customDimensions as cd where cd.index = 12) as cd1,
(SELECT cd.value FROM hits.customDimensions as cd where cd.index=29) as division,
hits.hitnumber

FROM 
  `dl-training-bigquery.NDA_CHAN*******51.ga_sessions_20191202` as session,
  unnest(hits) as hits
  
WHERE division = 'fsh'
ORDER BY hitnumber ASC

在此处输入图像描述

标签： sqlgoogle-analyticsgoogle-bigquerywhere-clausecross-join

解决方案

您不能SELECT在同一范围内重用子句中定义的列（将子句分开ORDER BY）。在这里，最简单的方法可能是将子查询移动到FROM子句：

SELECT 
    CONCAT(fullvisitorId, "-", CAST(visitstarttime AS STRING)) as session,
    RANK() OVER(PARTITION BY fullvisitorId, visitstarttime ORDER BY hitNumber) as rank, 
    dim1.cd1,
    dim2.division,
    hits.hitnumber
FROM `dl-training-bigquery.NDA_CHAN*******51.ga_sessions_20191202` as session
CROSS JOIN unnest(hits) as hits
CROSS JOIN (SELECT MAX(cd.value) as cd1 FROM hits.customDimensions as cd where cd.index = 12) as dim1
CROSS JOIN (SELECT cd.value as division FROM hits.customDimensions as cd where cd.index = 29) as dim2  
WHERE dim2.division = 'fsh'
ORDER BY hitnumber ASC

请注意，我简化了PARTITION BY窗口函数的子句：我认为您不需要在这里进行字符串连接，您可以使用两级分区。

我还将隐式连接更改为显式连接cross join。这不会改变逻辑，但在我看来使意图更清晰。

推荐阅读