replace - How to create list of files containing only filename in one set_fact task

Question

In Ansible 2.9 I am trying to create a list of files using the lookup plugin with the fileglob parameter that contains only the names of the files (not the path) and can be done in a single set_fact. My problem seems to be that I cannot figure out how to properly use regex when calling the replace method. I'm probably confusing some of the terminology there.

This is what I have so far, and once this works was going to send to split to build list.

- name: compile list of template files
  set_fact:
    list_of_files: "{{ lookup('fileglob', 'mydir/*').replace('/', '') }}"

But I cannot get any wildcard or regex I try to work. I have tried dozens of different options, that probably aren't worth repeating here.

标签： replaceansible

Answer 1

This is a non-regex solution using basename filer, this would use ansible's in-built logic to filter out the file name from the full path.

- name: compile list of template files
  set_fact:
    list_of_files: "{{ lookup('fileglob', 'mydir/*').split(',')|map('basename') |list}}"

map function feeds on an iterable(in this case output of lookup and split) and applies the function inside map (in this case basename) to all the elements of the iterable.