c - 3.3 C中读取的字符串不能倒序输出
问题描述
我想以相反的顺序将从文件 data01.in 读取的字符串写入 data03.out。但是,当我运行它时,两个文件具有相同的内容。我应该怎么办?之后,打开写入你创建的输出结果的文件和模型文件检查是否匹配,从头开始逐个字符比较,检查两个文件的内容是否匹配。我想找出它是什么并创建一个显示结果的程序,所以请告诉我如何创建该程序。
资源
#include <stdio.h>
#include <stdlib.h>
#define MAX 1000
int main ()
{
char in_filename [] = "data01.in";
char out_filename [] = "data03.out"
;
FILE * fpin, * fpout;
char buf [MAX];
int c;
int n;
int i;
/ * Open the input file. * /
if ((fpin = fopen (in_filename, "r")) == NULL)
{
printf ("Failed to open:% s \ n", in_filename);
exit (1);
}
/ * Open the output file. * /
if ((fpout = fopen (out_filename, "w")) == NULL)
{
printf ("Failed to open:% s \ n", out_filename);
fclose (fpin);
exit (2);
}
/ * Read data up to the maximum number of buffers * /
for (n = 0; n <MAX; ++ n)
{
if ((c = fgetc (fpin)) == EOF)
break;
buf [n] = (char) c; / * Don't forget to cast to char. * /
}
/ * If EOF is not reached even after the maximum number of buffers is reached, an error is processed as buffer overflow.
* /
if (n == MAX)
{
printf ("Buffer overflow! \ N");
exit (3);
}
/ * Output the contents of the buffer. * /
for (i = 0; i <n; ++ i)
{
fputc (buf [i], fpout);
}
/ * Don't forget to close each opened I / O file. * /
fclose (fpout);
fclose (fpin);
return 0;
}
数据01.in
A Turing machine is a mathematical model of computation that defines an abstract machine,[1] which manipulates symbols on a strip of tape according to a table of rules.[2]
Despite the model's simplicity, given any computer algorithm, a Turing machine capable of simulating that algorithm's logic can be constructed.[3]
"Turing machine" from Wikipedia(https://en.wikipedia.org/wiki/Turing_machine). (Access date: 2020/10/01)
数据03.out
)10/01/0202 :etad sseccA( .)enihcam_gniruT/ikiw/gro.aidepikiw.ne//:sptth(aidepikiW morf "enihcam gniruT"
]3[.detcurtsnoc eb nac cigol s'mhtirogla taht gnitalumis fo elbapac enihcam gniruT a ,mhtirogla retupmoc yna nevig ,yticilpmis s'ledom eht etipseD
]2[.selur fo elbat a ot gnidrocca epat fo pirts a no slobmys setalupinam hcihw ]1[,enihcam tcartsba na senifed taht noitatupmoc fo ledom lacitamehtam a si enihcam gniruT A
解决方案
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