reactjs - 如何使用 react-testing-library 检查material-ui MenuItem是否被禁用
问题描述
我正在使用 Material-UI 和 react 来构建一个Dropdown
组件。
下拉列表.tsx
import React from "react";
import ClickAwayListener from "@material-ui/core/ClickAwayListener";
import Grow, { GrowProps } from "@material-ui/core/Grow";
import Input from "@material-ui/core/Input";
import MenuList from "@material-ui/core/MenuList";
import Paper from "@material-ui/core/Paper";
import Popper from "@material-ui/core/Popper";
import MenuItem from "@material-ui/core/MenuItem";
export default function Dropdown(props: {
onSearch: (suggestion: string) => void;
}) {
const [searchText, setSearchText] = React.useState("");
const [open, setOpen] = React.useState(false);
let searchElement: null | HTMLElement = null;
const onSearchTextChange = (event: React.ChangeEvent<HTMLInputElement>) => {
setSearchText(event.target.value);
setOpen(true);
};
const openSearchSuggestion = () => {
setOpen(true);
};
const setSearchElement = (node: null | HTMLElement) => {
searchElement = node;
};
const closeSearchSuggestion = () => {
setOpen(false);
};
const handleOnClickAway = (event: React.MouseEvent<EventTarget>) => {
if (searchElement && searchElement.contains(event.target as HTMLElement)) {
return;
}
closeSearchSuggestion();
};
const handleSearchSuggestionClick = (suggestion: string) => (
event: React.MouseEvent<EventTarget>
) => {
props.onSearch(suggestion);
};
const searchSuggestionsRenderer = (suggestion: string, index: number) => {
return (
<MenuItem
key={index}
onClick={handleSearchSuggestionClick(suggestion)}
className="suggestion-item"
id={`suggestion-item-${index}`}
disabled={suggestion === "Criteria 2"}
>
{searchText} in {suggestion}
</MenuItem>
);
};
const popperTrans = ({ TransitionProps }: { TransitionProps: GrowProps }) => {
const searchSuggestions = ["Criteria 1", "Criteria 2"];
return (
<Grow {...TransitionProps} style={{ transformOrigin: "0 0 0" }}>
<Paper className="search-suggestions-paper">
<ClickAwayListener onClickAway={handleOnClickAway}>
<MenuList>
{searchText &&
searchSuggestions &&
searchSuggestions.map(searchSuggestionsRenderer)}
</MenuList>
</ClickAwayListener>
</Paper>
</Grow>
);
};
return (
<div>
<Input
inputRef={setSearchElement}
className="search-input"
placeholder="Search"
value={searchText}
onChange={onSearchTextChange}
onFocus={openSearchSuggestion}
data-testid="searchInput"
/>
<Popper
className="search-suggestion-popper"
open={open && searchText.trim().length >= 2}
anchorEl={searchElement}
placement="bottom-start"
transition={true}
>
{popperTrans}
</Popper>
</div>
);
}
我现在正在使用 react-testing-library 测试这个组件。我想检查下拉菜单中的第二个选项是否被禁用。我尝试检查单击第二个选项时未调用菜单项单击时调用的 onSearch 函数。
测试检查选项被禁用
test('that criteria 2 option is disabled', () => {
const props = { onSearch: jest.fn() }
const { getAllByRole, getByTestId } = render(<Dropdown {...props} />);
const Input = getByTestId('searchInput');
const TextBox = globalGetByRole(Input, 'textbox') as HTMLInputElement;
fireEvent.change(TextBox, { target: { value: 'test' } });
const MenuItems = getAllByRole('menuitem');
expect(MenuItems.length).toBe(2);
const Criteria2MenuItem = MenuItems[1];
fireEvent.click(Criteria2MenuItem);
expect(props.onSearch).toHaveBeenCalledTimes(0);
});
但这没有用。该函数被调用一次。为什么会发生这种情况,我该如何测试我想要测试的内容?
解决方案
当您禁用 Material-UIMenuItem
例如
<MenuItem disabled>
{...}
</MenuItem>
它将CSS 类添加到 DOM 中的aria-disabled="true"
元素。不是一个有效的按钮,所以你不能通过点击它来测试它。您需要检查它是否具有使用from的属性。Mui-disabled
li
li
aria-disabled
.toHaveAttribute()
jest-dom
expect(Criteria2MenuItem).toHaveAttribute("aria-disabled")
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