首页 > 解决方案 > 重塑具有开始和结束日期的数据集,以按天/月/季度创建时间序列计数汇总总和

问题描述

我有一个完全一样的数据集:

ProjectID   Start   End Type
Project 1   01/01/2019  27/04/2019  HR
Project 2   15/01/2019  11/11/2019  Marketing
Project 3   25/02/2019  30/07/2019  Finance
Project 4   22/02/2019  15/04/2019  HR
Project 5   05/03/2019  29/09/2019  HR
Project 6   11/04/2019  01/12/2019  Marketing
Project 7   29/07/2019  23/08/2019  Finance
Project 8   25/08/2019  23/12/2019  Operations
Project 9   31/10/2019  29/11/2019  Operations
Project 10  10/12/2019  25/12/2019  Operations

我想知道随着时间的推移,通过创建每日/每月/每季度的时间序列有多少项目是优秀的。我首先想创建一个整体项目的总和,然后还要知道有多少项目类型是优秀的。通过在 excel 中手动执行此操作,我相信我必须以某种方式重新采样数据,但我不确定如何以及在哪些维度上......当我在 excel 中执行此操作时,输出最终应如下所示:

在此处输入图像描述

在此处输入图像描述

在此处输入图像描述

如何使用 pandas 重塑数据以进行此分析?

标签: pythonpandasdataframe

解决方案


一种方法是获取一个日期范围(例如 1 年),然后将所有项目加入所有日期。我正在使用hvplot创建一个漂亮的最终结果的交互式绘图。

这是您的示例数据的工作示例:

from io import StringIO
import pandas as pd
import hvplot.pandas

text = """
ProjectID   Start   End Type
Project1   01/01/2019  27/04/2019  HR
Project2   15/01/2019  11/11/2019  Marketing
Project3   25/02/2019  30/07/2019  Finance
Project4   22/02/2019  15/04/2019  HR
Project5   05/03/2019  29/09/2019  HR
Project6   11/04/2019  01/12/2019  Marketing
Project7   29/07/2019  23/08/2019  Finance
Project8   25/08/2019  23/12/2019  Operations
Project9   31/10/2019  29/11/2019  Operations
Project10  10/12/2019  25/12/2019  Operations
"""

df = pd.read_csv(StringIO(text), header=0, sep='\s+')
df['Start'] = pd.to_datetime(df['Start'], dayfirst=True)
df['End'] = pd.to_datetime(df['End'], dayfirst=True)

# create a dummy key with which we can join all projects with all dates
df['key'] = 'key'

# create a daterange so that we can count all open projects for all days
df2 = pd.DataFrame(pd.date_range(start='01-01-2019', periods=365, freq='d'), columns=['date'])
# create a dummy key with which we can join all projects with all dates
df2['key'] = 'key'

# join all dates with all projects on dummy key = cartesian product
df3 = pd.merge(df, df2, on=['key'])

# check if date is within project dates
df3['count_projects'] = df3['date'].ge(df3['Start']) & df3['date'].le(df3['End'])

# group per day: count all open projects
group_overall = df3.groupby(
    'date', as_index=False)['count_projects'].sum()

# group per day per department: count all projects 
group_per_department = df3.groupby(
    ['date', 'Type'], as_index=False)['count_projects'].sum()

# plot overall result
plot_overall = group_overall.hvplot.line(
    x='date', y='count_projects',
    title='Open projects Overall',
    width=1000,
)

# plot per department
plot_per_department = group_per_department.hvplot.line(
    x='date', y='count_projects', 
    by='Type',
    title='Open projects per Department',
    width=1000,
)

# show both plots using hvplot
(plot_overall + plot_per_department).cols(1)

结果图:

使用 hvplot 绘制所有项目的计数


推荐阅读