node.js - 在for循环中调用多个API并使用node js得到一一响应
问题描述
我必须在 for 循环中使用 promise all 调用多个 API,但我得到的是非顺序格式的响应。例如,我有 3 行,但以 1、2、3 的顺序得到响应。首先获得第一行响应而不是第三行,然后获得第二行,但我需要以顺序格式获得响应,例如(1 行,2 行,3 行)。
result = '{"error_code":0,"err_desc":null,"data":[{"":"","name":"OTT, KATHRYN M","address":"3110 Horseshoe Trl, Glenmoore, PA","email":"","phone1":"(410) 599-2212","phone2":"(610) 827-9107","phone3":"(610) 308-4566","phone4":"(610) 506-1121","phone5":"(610) 469-0737","phone6":"(610) 942-4347","phone7":"323-7898","phone8":"(814) 371-6133","phone9":""},{"":"","name":"BELTRANTE, SUSAN E","address":"3 Rhoads Ave, Moorestown, NJ\"","email":"SUSAN.BELTRANTE@AOL.COM, JOE.BARGER@YAHOO.COM,","phone1":"(856) 266-0381","phone2":"(856) 273-0869","phone3":"(609) 266-0381","phone4":"(856) 235-3933","phone5":"","phone6":"","phone7":"","phone8":"","phone9":""},{"":"","name":"Manish","address":"4895 E American Beauty Dr, Tucson, AZ 85756","email":"abc@gmail.com","phone1":"(857) 266-0381","phone2":"(857) 273-0869","phone3":"(610) 266-0381","phone4":"(857) 235-3933","phone5":"","phone6":"","phone7":"","phone8":"","phone9":""}]}';
var i;
for (i = 0; i < result.length; i++)
//for (i = 0; i <= 0; i++)
{
var phone = result[i].phone9;
var name = result[i].name;
var address = result[i].address;
var email = result[i].email;
var phone1 = result[i].phone1;
var phone2 = result[i].phone2;
var phone3 = result[i].phone3;
var phone4 = result[i].phone4;
var phone5 = result[i].phone5;
var phone6 = result[i].phone6;
var phone7 = result[i].phone7;
var phone8 = result[i].phone8;
var addressinfo = address.split(',');
var street = addressinfo[0];
var city = addressinfo[1];
var state = addressinfo[2];
var zip = addressinfo[3];
Promise.all([
fetch('https://backend.mioym.properties/api/247/eppraisal?street='+street+'&zip='+zip),
fetch('https://backend.mioym.properties/api/247/zillow?street='+street+'&zip='+zip),
fetch('https://backend.mioym.properties/api/247/pennymac?address='+address),
fetch('https://backend.mioym.properties/api/247/chase?address='+address),
fetch('https://backend.mioym.properties/api/247/realtor?address='+address)
]).then(function (responses) {
// Get a JSON object from each of the responses
return Promise.all(responses.map(function (response) {
console.log("here"+i);
//console.log(response.json());
console.log(response.url);
return response.json();
}));
}).then(function (data) {
console.log("success"+i);
// Log the data to the console
// You would do something with both sets of data here
console.log(data);
}).catch(function (error) {
console.log("error"+i);
// if there's an error, log it
console.log(error);
});
}
所以请任何人建议我解决方案。
解决方案
Promise.all
块内的第二个then
不是必需的,因为它responses
已经包含解析的值。请注意,Promise.all
并行处理请求,但已解决的响应将按顺序排列。所以你可以简单地做:
Promise.all([
fetch('https://backend.mioym.properties/api/247/eppraisal?street=' + street + '&zip=' + zip),
fetch('https://backend.mioym.properties/api/247/zillow?street=' + street + '&zip=' + zip),
fetch('https://backend.mioym.properties/api/247/pennymac?address=' + address),
fetch('https://backend.mioym.properties/api/247/chase?address=' + address),
fetch('https://backend.mioym.properties/api/247/realtor?address=' + address)
]).then(function (responses) {
// Get a JSON object from each of the responses
return responses.map(function (response) {
console.log(response.url);
return response.json();
});
});